Argonath RPG - A World of its own
Argonath RPG Community => Speakerbox => Topic started by: Daco on May 23, 2011, 01:38:07 pm
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Feel free to share your problems and I will try to solve them here.
Regards. :roll:
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what iiiis:
1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1 x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x 1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1 x1x1x1x1x2x1x1x1x1x1x1x1x1x1x1x1x1x1x1x 1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1 x1x1x1x2x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x 1x1x1x1x1x1x1x1x1x1x1x1x2x1x1x1x1x1x1x1 x1?
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what iiiis:
1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1 x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x 1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1 x1x1x1x1x2x1x1x1x1x1x1x1x1x1x1x1x1x1x1x 1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1 x1x1x1x2x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x 1x1x1x1x1x1x1x1x1x1x1x1x2x1x1x1x1x1x1x1 x1?
8 smartass
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Nice thread tbf, it's good to see people helping others...I don't personally as I'm a major Maths "geek", but it is cool :)
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Well shit.
Anyway, this topic will be here if anyone want some help in math... :)
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True / Fals
a1 + a7 - a10 = -36
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Damn, where was this thread a few days ago when I had a math exam? :(
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True / Fals
a1 + a7 - a10 = -36
I don't get it.
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True / Fals
a1 + a7 - a10 = -36
FALSE
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FALSE
Assuming you're meant to be asking us to find the value of a you either mean...
-2a = -36
so a=18
or
a^1 + a^7 - a^10 = -36 which is outrageously negative. and not worth working out.
Okay here's one from Facebook (of all places. I know)
1+1 x 5 = ?
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1+1 x 5 = ?
6
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6
True, since else you have to (1+1)x5 then.
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Yeah, its quite shocking to see how many people over the age of 11 got that question wrong...
They were answering it step-by-step, which should have been corrected in primary school (under 11).
Brackets
Indices
Division
Multiplication
Addition
Subtraction
BIDMAS! :D
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Yeah, its quite shocking to see how many people over the age of 11 got that question wrong...
They were answering it step-by-step, which should have been corrected in primary school (under 11).
Brackets
Indices
Division
Multiplication
Addition
Subtraction
BIDMAS! :D
Brackets
Indicates
Division/Multiplication
Addition/Substraction
There is no rule that you have to do division before multiplication or vice versa. Same with addition and substraction.
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Brackets
Indicates
Division/Multiplication
Addition/Substraction
There is no rule that you have to do division before multiplication or vice versa. Same with addition and substraction.
Dude, you're challenging a guy who has been the top of his class for the past five years. It is BIDMAS. I don't give a crap about technicalities, as that is what I am going by. Got a problem? Go get a tissue, BIDMAS works for me and many others, so you can shove it :D
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Brackets
Indicates
Division/Multiplication
Addition/Substraction
There is no rule that you have to do division before multiplication or vice versa. Same with addition and substraction.
ACTUALLY
Ben is right, it IS in fact BIDMAS
1+1 x 5 = ?
Answe is 6
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I think the guy took my description wrongly...it is clear that it is irrelevant which order you use addition or subtraction, but the word for it is BIDMAS, thus why I wrote it the way I did :trust:
It kind of looks crap if I go:
Brackets
Indices
Division and Multiplication
Addition and Subtraction
My way of writing it looks better ;)
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>Implying Daco is smart at maths
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>Implying Daco is smart at maths
>impying you know how to imply
Apparently I've lost few years in the school...
Why can't we devide things by 0?
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Dividing by a number very close to zero gives you an astronomically huge number. You know that dividing a number by a fraction, say a/b, is the same as multiplying by b/a. So x divided by 1/10 is x * 10 = 10x. And x divided by 1/100 is 100x. And x divided by 1 / 100,000 is 100,000x. So as you divide by numbers closer and closer to zero, the result gets bigger and bigger.
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Dividing by a number very close to zero gives you an astronomically huge number. You know that dividing a number by a fraction, say a/b, is the same as multiplying by b/a. So x divided by 1/10 is x * 10 = 10x. And x divided by 1/100 is 100x. And x divided by 1 / 100,000 is 100,000x. So as you divide by numbers closer and closer to zero, the result gets bigger and bigger.
If people can't understand this.
Let's say we want to devide 5 by 0.
5/0.1 = 50
5/0.01 500
5/0.0001=5000
5/0.00001=50000
5/0.000001=500000
5/0.0000001=5000000
The closer we get to 0, the higher the result is.. It's called infinity.
(http://oumathclub.files.wordpress.com/2010/07/infinity.gif)
Hence limit exists.
lim x->0 (5/0) = infinity (depends on how to approach 0 to say it's plus infinity or minus infinity; if you approach with values closer to 0 on the right, you get +oo and if you approach on the left you get -oo).
Hope you understand. :D
>Implying Daco is smart at maths
orly
Post Merge: May 25, 2011, 09:42:58 am
I think the guy took my description wrongly...it is clear that it is irrelevant which order you use addition or subtraction, but the word for it is BIDMAS, thus why I wrote it the way I did :trust:
It kind of looks crap if I go:
Brackets
Indices
Division and Multiplication
Addition and Subtraction
My way of writing it looks better ;)
Here's a challenge for you:
8/4x6 = ?
PS: there is an answer. ;)
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The English National Curriculum for Numeracy taught be BODMAS at primary, obviously because indices were a top secret thing used by MI5. :m4:
BTW I hate all of those maths questions on FB. I hate even more the idiots who care enough to answer them wrong.
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I think the guy took my description wrongly...it is clear that it is irrelevant which order you use addition or subtraction, but the word for it is BIDMAS, thus why I wrote it the way I did :trust:
It kind of looks crap if I go:
Brackets
Indices
Division and Multiplication
Addition and Subtraction
My way of writing it looks better ;)
Yea, that's more like it.
also by Indicates you mean involution/exponentiation(?)
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The English National Curriculum for Numeracy taught be BODMAS at primary, obviously because indices were a top secret thing used by MI5. :m4:
:lol:
Your explanation makes more sense Daco.
Will probably help a few.
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So was this a math thread or a shooting thread?
8/4x6 = ?
PS: there is an answer. ;)
8.
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8.
He actually asked Ben the question.. :hah:
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He actually asked Ben the question.. :hah:
And she's mistaken too... :hit:
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Here's a challenge for you:
8/4x6 = ?
PS: there is an answer. ;)
Then you just follow the order, work it out as you go along.
8/4 is 2, Multiplied by 6 is 12
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Then you just follow the order, work it out as you go along.
8/4 is 2, Multiplied by 6 is 12
from left to right, just like reading a book or something. (or this text)
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Aha, I see what you did there ;)
I was taught both BODMAS and BIDMAS, but BIDMAS always made more sense to me, as I was never actually told what the O stood for in BODMAS :D
And yeah, I'd say 12 in that case, and it would work with the order of BIDMAS anyway :redface:
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Then you just follow the order, work it out as you go along.
8/4 is 2, Multiplied by 6 is 12
Yes that is correct.
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Dude, you're challenging a guy who has been the top of his class for the past five years. It is BIDMAS. I don't give a crap about technicalities, as that is what I am going by. Got a problem? Go get a tissue, BIDMAS works for me and many others, so you can shove it :D
Hey snob
(http://3.bp.blogspot.com/-dVcGIkBg058/TZigg13xZlI/AAAAAAAAAVo/kjNFhwVYorg/s400/math-jokes.jpeg)
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hey knob
IT RHYMES
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Might want to check the definition of a snob before calling me one :trust:
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Might want to check the definition of a snob before calling me one :trust:
A snob is someone who believes that some people are inherently inferior to him or her for any one of a variety of reasons, including real or supposed intellect, wealth, education, ancestry, taste, beauty, nationality, et cetera
I have seen at least twice you bringing up your "Majoring in Mathematics so shut up" attitude, so yeah in my book, it classifies under the word "snob".
No matter what is someones education we don't have to be knobs about it. ;)
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Nonetheless, France tops UK in math.
CASE CLOSED.
Next?
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Nonetheless, France tops UK in math.
CASE CLOSED.
Next?
A farmer has four straight pieces of fencing: 1, 2, 3, and 4 yards in length. What is the maximum area he can enclose by connecting the pieces? Assume the land is flat.
I'm stumped.
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A farmer has four straight pieces of fencing: 1, 2, 3, and 4 yards in length. What is the maximum area he can enclose by connecting the pieces? Assume the land is flat.
I'm stumped.
the piece's shape is a cube, right?
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the piece's shape is a cube, right?
>flat
>cube
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>flat
>cube
(http://www.myfacewhen.com/images/43.jpg)
I guess forming the cubes around each other won't change anything, area will still be A = 12+22+32+42 = 102 y2
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I have seen at least twice you bringing up your "Majoring in Mathematics so shut up" attitude, so yeah in my book, it classifies under the word "snob".
No matter what is someones education we don't have to be knobs about it. ;)
Majoring in Mathematics? I'm in England, not America, and I'm not in university or w/e they say that :trust:
In case you haven't noticed, I have admitted where I am wrong, so you can shove your book somewhere I can't see it.
My education is at a normal comprehensive school in the UK, so I can hardly be called a snob. I brought up my education at the beginning, so people could ask me questions if they wanted to, because I'm always there to help. I later brought it up because it was brought under question. Does that comply to your book, or are you narrow-minded enough not to have written anything like that in, as such?
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Topic creator is banned from forums, thread locked.
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Unlocked
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sup guise
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Under one condition, stay on topic please!
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Brackets
Indices
Division
Multiplication
Addition
Subtraction
BIDMAS! :D
For me it was taught as BEDMAS, where instead of Indices they called it Exponential... but same thing I guess ;)
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For me it was taught as BEDMAS, where instead of Indices they called it Exponential... but same thing I guess ;)
Same thing, yeah :)
Exponential graphs are equations with indices, so I guess it is anyway :P
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Yeah, its quite shocking to see how many people over the age of 11 got that question wrong...
They were answering it step-by-step, which should have been corrected in primary school (under 11).
Brackets
Indices
Division
Multiplication
Addition
Subtraction
BIDMAS! :D
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
FIX'T
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Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
FIX'T
Go check the British syllabus kthxbai.
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Go check the British syllabus kthxbai.
^
British Syllable clearly states BIDMAS, not PEDOMAN or wateva the fuck you mentioned
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Hey guys.
(http://i53.tinypic.com/2py3qxc.png)
And yes, you will be mad.
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Hey guys.
(http://i53.tinypic.com/2py3qxc.png)
And yes, you will be mad.
a)4
b)25
:banana:
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a)4
b)25
:banana:
(http://media.tumblr.com/tumblr_lbyq4bHX5S1qak47i.jpg)
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a)4
b)25
:banana:
well, shit
(http://i55.tinypic.com/34hz53m.png)
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Hey guys.
(http://i53.tinypic.com/2py3qxc.png)
And yes, you will be mad.
I dont get it, why should this be complicated or confusing?
How about this:
10+5x2/3x8-3=?
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I dont get it, why should this be complicated or confusing?
How about this:
10+5x2/3x8-3=?
10+5x2=20
3x8-3=21
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10+5x2=20
3x8-3=21
Completely wrong, next.
Btw those are not two different equations.
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Wrong, next.
explain
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explain
Let others try first.
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I dont get it, why should this be complicated or confusing?
How about this:
10+5x2/3x8-3=?
oh, then 33 2/3
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I dont get it, why should this be complicated or confusing?
How about this:
10+5x2/3x8-3=?
If you mean (10+5x2)/(3x8-3)
i.e.
10+5x2
3x8-3
then = 20/21
however
10+5x(2/3)x8-3= 7+(80/3) = 33 2/3
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3 = square number
N3A + N3B + N
Find A and B with Simultaneous equation
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3 = square number
N3A + N3B + N
Find A and B with Simultaneous equation
With one equation :trust:
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oh, then 33 2/3
Yea this is correct.
Also Cofi the one I gave was supposed to be confusing because if you follow PEMDAS or BODMAS to the letter you will get the wrong answer. People don't know or forget that the DM and the AS are actually equivalent and that you read them left to right if written as such.
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3 = square number
N3A + N3B + N
Find A and B with Simultaneous equation
N(3A+1)=-3NB => 3A+1=-3B => 3(A+B)=-1
A+B=-1/3
So infinite amount of correct answers. Unless, you specify what you mean by 3= square number.
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PEMDAS
( ) exponets multi/divi add/sub (left from right) pretty simple and my math teacher told me not to use it, but I still do and get shit correct.
Easy way to remember: Please Excuse My Dear Aunt Sally or Please Excuse My Dope Ass Swag
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So infinite amount of correct answers. Unless, you specify what you mean by 3= square number.
N ^3 or like 2^2 = 4
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N(3A+1)=-3NB => 3A+1=-3B => 3(A+B)=-1
A+B=-1/3
So infinite amount of correct answers. Unless, you specify what you mean by 3= square number.
What you're doing isn't possible, since he never said that N3A + N3B + N = 0. He never gave an equation.
He just gave:
N3A + N3B + N
This is not an equation. However, this would be an equation:
N3A + N3B + N = 0
Hawke's assignment makes no sense whatsoever. :D
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I need help with Physcis, it is an assignment regarding Kinetic energy;
Someone knows how to solve this? I tried using the formula Ek=mv^2/2
Also the speed has to be converted to m/s? If so then I guess 55/3.6=15.28m/s
Do I need to count the potential energy aswell?
A roller coaster trolley and its passengers have a mass 840 Kg. The trolley comes over the top of the first hill with a speed of 55km/h. The hill is 85.0 m above the ground. The trolley goes down the first hill and up the rest of the second hill 64.0 m above ground. Ignore the effects of frictional forces. What is the kinetic energy of the trolley at the top of the second hill?
Help :(
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I need help with Physcis, it is an assignment regarding Kinetic energy;
Someone knows how to solve this? I tried using the formula Ek=mv^2/2
Also the speed has to be converted to m/s? If so then I guess 55/3.6=15.28m/s
Do I need to count the potential energy aswell?
A roller coaster trolley and its passengers have a mass 840 Kg. The trolley comes over the top of the first hill with a speed of 55km/h. The hill is 85.0 m above the ground. The trolley goes down the first hill and up the rest of the second hill 64.0 m above ground. Ignore the effects of frictional forces. What is the kinetic energy of the trolley at the top of the second hill?
Help :(
a = situation on the top of hill #1
b = situation on the top of hill #2
v_a = 55 / 3.6 = 15.28 ms^-1
g = 9.81 ms^-2
h_a = 85.0 m
h_b = 64.0 m
Ignore frictional forces, means no loss of energy. So:
E_total,a = E_total,b
E_kin,a + E_g,a = E_kin,b + E_g,b
E_kin,b = E_kin,a + E_g,a - E_g,b
E_kin,b = 0.5mv_a^2 + mgh_a - mgh_b
E_kin,b = 0.5 * 840 * 15.28^2 + 840 * 9.81 * 85.0 - 840 * 9.81 * 64.0 = 271109 = 2.7 * 10^5 J
So the kinetic energy on the second hill is 2.7 * 10^5 J(oule).
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a = situation on the top of hill #1
b = situation on the top of hill #2
v_a = 55 / 3.6 = 15.28 ms^-1
g = 9.81 ms^-2
h_a = 85.0 m
h_b = 64.0 m
Ignore frictional forces, means no loss of energy. So:
E_total,a = E_total,b
E_kin,a + E_g,a = E_kin,b + E_g,b
E_kin,b = E_kin,a + E_g,a - E_g,b
E_kin,b = 0.5mv_a^2 + mgh_a - mgh_b
E_kin,b = 0.5 * 840 * 15.28^2 + 840 * 9.81 * 85.0 - 840 * 9.81 * 64.0 = 271109 = 2.7 * 10^5 J
So the kinetic energy on the second hills is 2.7 * 10^5 J(oule).
This.
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a = situation on the top of hill #1
b = situation on the top of hill #2
v_a = 55 / 3.6 = 15.28 ms^-1
g = 9.81 ms^-2
h_a = 85.0 m
h_b = 64.0 m
Ignore frictional forces, means no loss of energy. So:
E_total,a = E_total,b
E_kin,a + E_g,a = E_kin,b + E_g,b
E_kin,b = E_kin,a + E_g,a - E_g,b
E_kin,b = 0.5mv_a^2 + mgh_a - mgh_b
E_kin,b = 0.5 * 840 * 15.28^2 + 840 * 9.81 * 85.0 - 840 * 9.81 * 64.0 = 271109 = 2.7 * 10^5 J
So the kinetic energy on the second hills is 2.7 * 10^5 J(oule).
Thanks for the help! :D
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N ^3 or like 2^2 = 4
Ah, you know we have commands for typing it like that :) anyway then you'll get
3N2(A+B)= -1
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Ah, you know we have commands for typing it like that :) anyway then you'll get
3N2(A+B)= -1
Christ thats a tuffy. Specially at this time of night.
I'll get it.
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Thanks for the help! :D
No problem. ;)
Now here's one for you guys, for fun.
(x^2 + 6)^9. Write out it (leaving no more brackets), and yes, you don't need a computer program to do so.
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No problem. ;)
Now here's one for you guys, for fun.
(x^2 + 6)^9. Write out it (leaving no more brackets), and yes, you don't need a computer program to do so.
(http://i53.tinypic.com/fd7f5y.png)
And that makes...
(a+b)9=a9+9a8b+36a7b2+84a6b3+126a4b5+126a3b6+84a2b7+36ab8+9+b9
So....
(x2+6)9=x18+
54x16+216x14+18144x12+163296x10+979776x8+3919104x6+10077696x4+15116544x2+10077696
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(http://i53.tinypic.com/fd7f5y.png)
And that makes...
(a+b)9=a9+9a8b+36a7b2+84a6b3+126a4b5+126a3b6+84a2b7+36ab8+9+b9
So....
(x2+6)9=x18+
54x16+216x14+18144x12+163296x10+979776x8+3919104x6+10077696x4+15116544x2+10077696
Correct. :)