Homework Section

[duffman]

t = +oo

checkmate

t = x you don't know, thats what you have to find. Not by those equations, but by the calculator.

[Daco]

t = x you don't know, thats what you have to find. Not by those equations, but by the calculator.

ok you're banned from posting










seriously man stop trolling
Post Merge: April 22, 2012, 11:49:12 pm

It makes sense since the solution can behave according to the function no matter what amount of solute is added into the solvent; it doesn't have to relate to the first question although the result from the first question can come in handy when checking the result you get. The problem is that the function doesn't allow you to determine how much time it takes to dissolve something as it shows the amount of remaining solute. You could try solving with q as 0 since then all solute is dissolved, but then you wouldn't be able to solve the equation. :razz:

i don't understand...

how the fuck can you dissolve 20 grams if the maximum solvant you can get from the equation is 12g....????
excluding of course, the time variable t is negative (which is illogical)

[duffman]

ok you're banned from posting










seriously man stop trolling

man wtf, I need to get my last 5 points on that shit. I just need that but okay my teacher will do that in the class and I will show to ya'll, holmes

[Daco]

ok add [email protected] or [email protected] so i can teach u ok???
ty.

[ElMartu]

man why you involving me on this

i like, lost myself as soon as you posted the damn equation

[Daco]

man why you involving me on this

i like, lost myself as soon as you posted the damn equation

add this guy ^ ok?

fast im gonna sleep soon xoxo

[Patton]

It makes sense mathematically since you get a number in the end, but physically it is nonsense since you can't get negative time. :razz: You can use the results from both questions to conclude and argue that any amount of solute over 12g does not dissolve in the water; instead, it will form a saturated solution with a layer of sediment on the bottom of the glass. So yes, t=∞ would be a very acceptable.

[Jubin]

Duffman, for the sake of these guys arguing, please check again the initial equation - especially if the denominator is has -3 or -3' or maybe even -3^t.

[duffman]

OKAY my teacher made that shit wrong, its only -3 not -3'...


sorry mans

[Daco]

Hello.

[Mikal]

1+1=2

[Daco]

1+1=2

1+1 = 1

its 2012 u no  ? ? ? ? ?

[Mopreme]

Hi, everyone.
If there is anyone out there who is good at analyzing sentences (finding direct object, indirect object etc. as well as clauses such as post modifying clauses, adverbial clauses etc.) then please PM me. I would really appreciate some help here, and I am willing to pay for it.
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[Marcel]

Didn't even knew this topic existed!

If anyone needs help, just let me know, i can help on the following subjects:

- Aviation (aerodynamics, physics, maths, mechanics, air data systems, cockpit instruments, weather, air law and regulations and more)
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[duffman]

History of France anyone???