Homework Section

[Kitsune]

Got problems with this one.. Not sure about it.. Please help Picture uploaded

Initial equation:
(2ac)³b⁵4(ab)²
(ba2)²

Rearranged to a more proper format:
4b⁵(2ac)³(ab)²
(2ab)²

Brackets expanded:
4b⁵2³a³c³a²b²
2²a²b²

Grouped like types:
32a⁵b⁷c³
4a²b²

Canceled out values:
8a³b⁵c³

[Jubin]

Typical asian : ))
But one of the few Argonather, who doesn't make me lose all hope in the humanity.

[Quang]

Typical asian : ))

Im no typical asian, I suck at math xD

[ShawmMoe]

Math question. Picture uploaded. Please explain how I can find the answer...

[Jubin]

well first thing I noticed is that 2a/(4b+2a) is actually 2a/2(2b+a) => a/2b+a but hey now you have (3a-a)/(2b+a) = 2a/2b+a

EDIT: picture added

[9r2e5i3k]

well first thing I noticed is that 2a/(4b+2a) is actually 2a/2(2b+a) => a/2b+a but hey now you have (3a-a)/(2b+a) = 2a/2b+a

EDIT: picture added

is it legal to do this?
2a₁ / 2b + a₁ =

2  / 2b + 1 =

b + 1/2

[Kitsune]

is it legal to do this?
2a₁ / 2b + a₁ =

2  / 2b + 1 =

b + 1/2

First off, if you want to to divide the equation by 'a', then you need to include an equality, and do the same on the other side of the equation, so that it balances out. Otherwise, the most you can do is take a factor of 'a', but the 'a' would still exist, so your second equation should actually look like 'a(2/(2b)+1)'.

Secondly, I see that you've turned, '2/(2b)+1', into 'b+1/2'. I don't see how you figured that out, but it isn't a valid conversion.

[Jubin]

is it legal to do this?
2a₁ / 2b + a₁ =

2  / 2b + 1 =

b + 1/2

so in otherwords of Kitsune's text - no it's illegal and you should be suspected.
Well lets assume, that a= 3 and b=2. at first you have 2*1/(2*2+1) = 3/7  after the first you got 2/2b+1 which is 2/5 and 3/7 does not equal to 2/5

[Melvin]

so in otherwords of Kitsune's text - no it's illegal and you should be suspected.
Well lets assume, that a= 3 and b=2. at first you have 2*1/(2*2+1) = 3/7  after the first you got 2/2b+1 which is 2/5 and 3/7 does not equal to 3/7

Congratulations, You just brought me some Headache :O

[Gerrie = Banned (Daco)]

Questions please.

[Yihka]

Uhm

Why do you all say it so hard? O.o

a2 + b1
a2 + b2

See it like this

a2 + b1                            a2+b2

A = Apple b = bean

So the firstp erson has 2 apples and 1 bean

The other guy has 2 apples and 2 beans.

a2 + b1                           a2+b2
-a2                                 -a2

You begin getting the apples away. They both have the same amount.

You get:

b1                                 b2
-b1                                -b1

You get 1 bean away, because you can at both.

What do you get?

b1.



But I forgot what you have to do afterwards...
But maybe that is something else... lol..

[ShawmMoe]

What about this one:

Santa Claus has a pair of trousers on. The trousers is held up by a belt.
Santa Claus likes good food and Christmas parties and expect to take at 3 cm in thickness, diameter.
How many holes must be enlarged to their belts over the festive season when there is 2.5 cm
between the holes?

[Jubin]

Answer: none - Santa Claus just takes his pants off.

[Gerrie = Banned (Daco)]

Answer: none - Santa Claus just takes his pants off.

Yup, tricky question.

[ShawmMoe]

LOL it's really a math question... There is an answer existing, WITH NUMBERS...