Argonath RPG - A World of its own

Argonath RPG Community => Speakerbox => Topic started by: Custom on January 18, 2009, 04:11:31 pm

Title: Homework Section
Post by: Custom on January 18, 2009, 04:11:31 pm
Are you sitting alone at home, and stuck with your homewoks?
You will be helped as much as possible by replieing here.
Try us out with any subjects, math, biology, geography, physics/chemistry, anything :)
Who knows? Maybe you'll get surprised, and get the excact help your looking for, perhaps even in foreign languages too:)
But for your own sake, do not ask for help if you haven't tried to do the job by yourself ;)
Try by yourself before you ask :)
Everyone is always welcome to ask for the help they need :)
I think that this topic will be a very helpfull topic for many people :)
Thanks.

Best Regards
Custom
Title: Re: Homework Section
Post by: Alsatian on January 25, 2009, 06:32:22 pm
Work out the function that generate the following mixed outputs

a). [3, 0, 4, 1] ---> [9, 1, 13, -3]

b). [4, -2, 5, 0] ---> [13, -2, -8, 10]

c). [3, -1, 3, 0] ---> [-2, 18, 3, 23]

d.) [5, 0 -1, 6] ---> [35, -1, 5, 41]

Hint: Put them in order first!

If its possible, please explain how to work this out, im so stuck, thank you
Title: Re: Homework Section
Post by: Jubin on January 25, 2009, 06:57:05 pm
Work out the function that generate the following mixed outputs

a). [3, 0, 4, 1] ---> [9, 1, 13, -3]

b). [4, -2, 5, 0] ---> [13, -2, -8, 10]

c). [3, -1, 3, 0] ---> [-2, 18, 3, 23]

d.) [5, 0 -1, 6] ---> [35, -1, 5, 41]

Hint: Put them in order first!

If its possible, please explain how to work this out, im so stuck, thank you
a) First is y=4x-3
b) y= 3x-2
c) is there a typo as you got two times number 3's as x'es. and two different y's for them
d) y= 6x+5



First you got your X's in order [0,1,3,4] and Y's [-3,1,9,13]. And you know that this function is linear [ if you don't know draw this function ]. Now linear function's main equation is y=mx+b. Now replace the matching X and matching Y to that main equation. First I recommend to replace the 0 from x's. so you get the equation -3=m*0+b. Now as any number multiplied by 0 is zero you get -3=b. You got your b value. Now you put b value into the second equation what you get, when you replace the second X's and Y's [ in this case 1 an 1] to the main equation. so you get 1=m*1-3 (-3 is the value of b] so we bring the -3 to the other side and we get 4=m. Now replace m and b to the main equation and there you go y=4x-3.

I'm sure someone else can explain it to you much better and knows an easier way.

 :ps: I got those answers with thx to my program what I have on PC :)
Title: Re: Homework Section
Post by: Alsatian on January 25, 2009, 07:40:13 pm
Jubin, Jubin, I cant thank you enough, you have just saved me, thank you sooo much!  :pop:

 :ps: Whats the program you use?
Title: Re: Homework Section
Post by: Jubin on January 25, 2009, 08:42:16 pm
oh mostly this kind of exercises are being solved with equation systems. Let me demonstrate it on the b) exercise
first still put them in order:
X's [-2,0,4,5] Y's [-8,-2,10,13]. Now take 2 random X's and 2 random Y's [ in this case I take pairs [-2,-8] and [4,10] and put them into the main equation y=mx+b. You'll get the equation system:

-8=m*-2+b => -2m+b=-8
10=m*4+b =>  4m+b=10
now from one of this equation we express either m or b. I take the first equation and b. So it goes like this -2m+b=-8 => b=-8+2m. Now that equation we replace to the second equation.
It goes like this 4m+b=10 => 4m+(-8+2m)=10 => 6m-8=10 => 6m=18 |: 6 => m=3. Now we know what is the value for m also we know that
b= -8+2m therefore b=-8+2*3 => b= -2.
Replace m and b to the main equation and you get y=3x-2.

Edit: Even faster way to solve is this: After you've got your equation system:
-2m+b=-8
 4m+b=10
you subtract them from each other
 -2m+b=-8
-                 it's like    -2m+b-(4m+b)=-8-10
  4m+b=10
=-6m=-18 | : (-6) => m=3. Replace the value of m in any of the equations to get the value of b.

 :ps: The program I use is called Datastudio and it is meant for executing experiments and then analyzing the results.
Title: Re: Homework Section
Post by: Wash on January 25, 2009, 10:33:34 pm
Please lock this!:P

Why should I talk about homework in my free time?

Don't talk about it then.. it's for people to request help when they are stuck at something with their homework.
Title: Re: Homework Section
Post by: Dmitry on January 25, 2009, 10:40:12 pm
Oh my god.
I think I need to press X.

How u guys now this ?:P

:lol: Some cool place called 'school' xD

I think I might be need some help soon.

Jubin ur damn smart btw.

Title: Re: Homework Section
Post by: Alsatian on January 26, 2009, 12:32:28 am
Thanks Jubin :)

I can help, Im good at maths, sometimes I just need to remember the basics, I complicate it for myself, meh  :(
Title: Re: Homework Section
Post by: stof on January 26, 2009, 02:46:24 am
this topic is gonna come in very usefull cos i suck at school and will be lucky to pass 9th grade :(
Title: Re: Homework Section
Post by: rJCaiG on January 26, 2009, 04:33:53 am
this'll help when i can't be bothered doing some homework this year  :lol: good idea
Title: Re: Homework Section
Post by: Clooak on January 26, 2009, 09:40:49 pm
Decide f´´(x) if f(x) = (5x^3 - 8x^2)/10

Anyone know the answer? :=)

Nevermind I found out the solution.

For those who are woundering :) Heres how to solve it

f´(x)= (15x^2 - 16x)/10 = f(x)= (30x - 16x)/10
f(2)= (30x - 16x)/10
(30*2- 16*2) /10 = (60-32)/10 = 28/10=2.8

Correct answer would be = 2.8 :)
God I love math
Title: Re: Homework Section
Post by: Chuck_Norris on January 26, 2009, 09:44:12 pm
We got a assignement to find a song wich could be used for a thriller.
does anyone know what songs could be used for it , and could link me to youtube?
very much appreciated u guys !
Title: Re: Homework Section
Post by: Kitsune on January 26, 2009, 10:00:13 pm
Decide f´´(x) if f(x) = (5x^3 - 8x^2)/10

Anyone know the answer? :=)

3x-1.6
Title: Re: Homework Section
Post by: Kitsune on January 26, 2009, 10:14:44 pm
Your solution is wrong because you forgot to change the 16x to 16 when you got the second derivative.

The correct solution:
f(x)=(5x^3-8x^2)/10
f'(x)=(15x^2-16x)/10
f''(x)=(30x-16)/10
      =3x-1.6
f''(2)=3*2-1.6
      =4.4

What you did:
f(x)=(5x^3-8x^2)/10
f'(x)=(15x^2-16x)/10
f''(x)=(30x-16x)/10
      =3x-1.6x
f''(2)=3*2-1.6*2
      =2.8
Title: Re: Homework Section
Post by: Clooak on January 26, 2009, 10:40:41 pm
My bad, your correct :) I forgot to derive as u said 16x :)

Your solution is wrong because you forgot to change the 16x to 16 when you got the second derivative.

The correct solution:
f(x)=(5x^3-8x^2)/10
f'(x)=(15x^2-16x)/10
f''(x)=(30x-16)/10
      =3x-1.6
f''(2)=3*2-1.6
      =4.4

What you did:
f(x)=(5x^3-8x^2)/10
f'(x)=(15x^2-16x)/10
f''(x)=(30x-16x)/10
      =3x-1.6x
f''(2)=3*2-1.6*2
      =2.8
Title: Re: Homework Section
Post by: Jubin on January 27, 2009, 01:32:57 am
Am I the only one who thinks that in the western world, beside Japanese also Aussies are good in mathematics. (stereotyping)
Title: Re: Homework Section
Post by: Trent on January 27, 2009, 01:43:58 am
Nope, i suck at maths lol
Title: Re: Homework Section
Post by: Matthew_Cipricla on January 27, 2009, 03:04:46 am
Am I the only one who thinks that in the western world, beside Japanese also Aussies are good in mathematics. (stereotyping)

Yes, I think all of America stereo types Asians to be very very smart.
Title: Re: Homework Section
Post by: Cane on January 27, 2009, 03:22:32 am
Yes, I think all of America stereo types Asians to be very very smart.

That's usually because Asian kids are disciplined by their parents, usually forced to read or go to after-school educational activities and stuff... Luckily my parents don't force me to do that :D
Title: Re: Homework Section
Post by: Wayne on January 27, 2009, 03:26:46 am
Help me guys, this problem is awesome :S it's for 10 points to deliver 1 week :S
Quote
Three salesmen had arrived at the same time at the only motel in town with a vacancy. The motel had only one room vacant but the men, all road weary from driving long distances, decided to share the room and split the cost.

"How much for the room?" they asked.

"Thirty dollars" replied the clerk. (I know what you are thinking - $30 for a room, give me a break - think of it as a small room in a small town. <g>)

Each salesman handed the clerk $10 (3 X $10 = $30) and they went to the room.

After the men left the lobby, the clerk rechecked the room rate and discovered it was only $25 and not the $30 she had charged the men.

Not knowing how to divide the $5 overcharge, she decided to give each man $1 and pocket the remaining $2 ( 3 x $1 = $3 + $2 = $5).

Each guest had now paid $9 ( $10 - $1 =$9) for the room making the total paid $27 (3 x $9 = $27). The clerk had pocketed $2 bringing the total to $29 ($27 +$2 = $29) leaving $1 unaccounted for ($30 - $29 = $1).

Those are the circumstances. The problem lies in the unaccounted for $1. Where did it go?

There is one, and only one, answer to this math problem. To help you solve it, here are some hints.

1. The $1 was not charged as any sort of tax

2. The clerk pocketed $2 and not $3

3. The men received $1 each and not $1.33

4. The $1 was not spent in the vending machine or at the bar

5. She was the only clerk on duty when the men arrived

6. She did not lose the $1

7. She did not give the $1 to a friend or anyone else

8. This problem is not about how much each man paid

9. The dollar was not put back into the register
Title: Re: Homework Section
Post by: Cutt3r on January 27, 2009, 03:54:07 am
Meh, nice one. I think this is how it works :p

They ultimately had to pay 25 bux, not 24(the problem says "9x3". Thats 27. But I went a step further and 8x3 is only 24 and they paid 25) ;). 25/3 = 8.33 per person. Plus, each person paid one extra dollar, so thats 9.33 per person.

9.33 x 3 persons = 28. Plus the 2 dllars that the clerk pocketed makes it 30.

I think thats it.   

 :ps: Yes the question says "its not about how much each man paid" but my lil brain comes up with only this answer
Title: Re: Homework Section
Post by: Dmitry on January 27, 2009, 06:32:25 am
Am I the only one who thinks that in the western world, beside Japanese also Aussies are good in mathematics. (stereotyping)
Well.. Israel counts in as a westren country, and 85% of the kids in school suck at maths... and 55% from the kids that suck at math, are actually failing in math..
Luckly I'm good at maths :D
Title: Re: Homework Section
Post by: Kitsune on January 27, 2009, 06:53:18 am
Australians in no way stand out for their competence in mathematics and our education system is of a lower standard then a lot of other countries (especially Asian countries). This is especially true with the "original Australians" ie. Aboriginals and massive bogans (if you don't know what a bogan is, think of the Austrlian version of an American hillbilly), but due to so many more immigrants now, things are more spread out. I'm not being racist, I'm just telling it as it is and any Australian would know this. However, Australian Asians stand out within Australia because as Cane mentioned, typical Asian parents are very strict and quite involved in the education of their children.
Title: Re: Homework Section
Post by: stof on January 27, 2009, 02:26:13 pm
hmm Australians like me arent smart ive failed math ever since first grade :/
Title: Re: Homework Section
Post by: Chuck_Norris on January 27, 2009, 04:59:20 pm
We got a assignement to find a song wich could be used for a thriller.
does anyone know what songs could be used for it , and could link me to youtube?
very much appreciated u guys !

not needed anymore, i got a 0 on the task lol :p
Title: Re: Homework Section
Post by: Matthew_Cipricla on January 28, 2009, 11:43:44 pm
Use the 4 step math plan, I need someone to help me figure out this problem... http://teacher.scholastic.com/lessonrepro/lessonplans/steppro.htm (http://teacher.scholastic.com/lessonrepro/lessonplans/steppro.htm)

Quote
A banquet hall contains only chairs and round tables, and has 10 chairs at every table. Each table has 8 legs and each chair has 4 legs. The total number of legs on all of the chairs and tables is 960. What is the maximum number of people that can be seated (one per chair) at a banquest hall?

This question its self is easy, its 200 chairs, 20 tables, and 200 people. But how the hell am I supposed to write out this "plan" of solving it.... I just dont get the 4 step plan and hopefully someone else  does.
Title: Re: Homework Section
Post by: Cutt3r on January 29, 2009, 04:04:59 am
Use the 4 step math plan, I need someone to help me figure out this problem... http://teacher.scholastic.com/lessonrepro/lessonplans/steppro.htm (http://teacher.scholastic.com/lessonrepro/lessonplans/steppro.htm)

This question its self is easy, its 200 chairs, 20 tables, and 200 people. But how the hell am I supposed to write out this "plan" of solving it.... I just dont get the 4 step plan and hopefully someone else  does.

My answer :

Step 1

Let the number of tables be 'x' and the number of chairs be 'y'
8x + 4y = 960 (given in the question)

Step 2

In one set of tables and chairs we have one table and 10 chairs. (given in the question)
Total number of legs in one set = 8 legs(for the table) + 40 legs(for the 10 chairs) = 48

Step 3

Total number of sets = 960/48 = 20.
Each set has 1 table. Therefore number of tables = 20.

Step 4

Substituting the value obtained in step 3 in the equation in step 1 :

8x20 + 4y = 960
4y = 960-160
4y = 800 or y =200
Title: Re: Homework Section
Post by: Matthew_Cipricla on January 29, 2009, 04:17:59 am
Wow, just wow  :eek: I am defintly using that for the assignment. Its 10 times better then what I wrote up. And looks way more neat in that form. Thank you alot!!
Title: Re: Homework Section
Post by: Abraham on January 29, 2009, 07:53:54 am
Wish I was still in school... oh well, back to work. :(
Title: Re: Homework Section
Post by: Alsatian on January 30, 2009, 04:26:00 pm
Wish I was still in school... oh well, back to work. :(

I always had the "I hate school" attitude, but now that Im coming closer and closer to the end of my school life, im starting to realise school is the best time of your life, once its over, you wont see all your friends etc. Everything changes

I hate change  :(
Title: Re: Homework Section
Post by: Abraham on January 30, 2009, 04:35:54 pm
I always had the "I hate school" attitude, but now that Im coming closer and closer to the end of my school life, im starting to realise school is the best time of your life, once its over, you wont see all your friends etc. Everything changes

I hate change  :(
This is the part I miss, friends and stuff, but school itself sucks.
Luckily for me I still see allot of the guys / girls I knew from school, except for the geeky ones... I don't think they liked me D:

/me was a bully...


EDIT: Anyhow I'll leave this homework topic, nothing for me :P
bie.
Title: Re: Homework Section
Post by: Davron on January 30, 2009, 04:42:25 pm
O wow i never snew about this i would use this alot  :redface:
Title: Re: Homework Section
Post by: Custom on February 24, 2009, 04:58:10 pm
Hello :)

Subject: English
Problem: Can't find a word in english (I have about over eating)..
Here is a little where I use the word on danish, try regonize the word in english, please.

As with anorexia, bulimia and over eating is the food such a large occupation that prevents the patient from leading a normal life. But as anorexia and bulimia is focused on the quantity of food is (ortorektikeren) focused on food quality and rituals. (Ortorektikeren) is decidedly not afraid to be fat and do not want to be particularly thin - she would just like to eat healthy. (Ortoeksi ) and anorexia is still not the same, even if they may resemble each from the outside, because there are different demands and different motivation behind the desire to control the food.

The word I need to know is typed in ()
The word wrote with bold, is the main word (not bent)
I guess that was it :)
Thanks for reading :)

-Custom
Title: Re: Homework Section
Post by: Cutt3r on February 26, 2009, 04:08:32 am
I am not Danish. I used a combination of  google pages and wikipedia and came up with the following results:

Ortoeksi - Orthorexia
Looking at the sentence and context for "ortorektikeren" i felt that you could use the term syndrome as Orthorexia is a Culture-specific syndrome, as categorized by Wikipedia. My suggestion is as under :

As with anorexia, bulimia and over eating is the food such a large occupation that prevents the patient from leading a normal life. But as anorexia and bulimia are focused on the quantity of food, the Orthorexia syndrome is essentially being focused on food quality and rituals. This syndrome is decidedly not being afraid to be fat and not wanting to be particularly thin - she would just like to eat healthy. Orthorexia and anorexia are still not the same, even if they may resemble each from the outside, because there are different demands and different motivation behind the desire to control the food.

Changes have been indicated in bold.

PS: The first sentence is gramatically incorrect. As I dont know what it means, I havent corrected it.
Title: Re: Homework Section
Post by: Custom on February 27, 2009, 01:37:44 pm
I am not Danish. I used a combination of  google pages and wikipedia and came up with the following results:

Ortoeksi - Orthorexia
Looking at the sentence and context for "ortorektikeren" i felt that you could use the term syndrome as Orthorexia is a Culture-specific syndrome, as categorized by Wikipedia. My suggestion is as under :

As with anorexia, bulimia and over eating is the food such a large occupation that prevents the patient from leading a normal life. But as anorexia and bulimia are focused on the quantity of food, the Orthorexia syndrome is essentially being focused on food quality and rituals. This syndrome is decidedly not being afraid to be fat and not wanting to be particularly thin - she would just like to eat healthy. Orthorexia and anorexia are still not the same, even if they may resemble each from the outside, because there are different demands and different motivation behind the desire to control the food.

Changes have been indicated in bold.

PS: The first sentence is gramatically incorrect. As I dont know what it means, I havent corrected it.


Thanks very much for your help! Very helpful :)
Title: Re: Homework Section
Post by: KRiBaH on February 28, 2009, 10:22:09 pm
Comon post some physics, indians are quite good at science. Thoughfully im indian too but living in spain, got a very hard topic in maths and physics! i love them!
Title: Re: Homework Section
Post by: Gandalf on February 28, 2009, 10:45:23 pm
Comon post some physics, indians are quite good at science. Thoughfully im indian too but living in spain, got a very hard topic in maths and physics! i love them!
Ok, an old one but a good one...
A guy on the 3rd floor of an apartment building drops a flower pot on to the roof of a car.
Each floor of the apartment building is 2.5m high, the flower pot weighs 1 kg, and the maximum roof load of the car is 50Kg.
Will the flower pot only dent the roof or break it ?
Please show the calculations in your answer.
Title: Re: Homework Section
Post by: Alsatian on February 28, 2009, 11:08:34 pm
Ok, an old one but a good one...
A guy on the 3rd floor of an apartment building drops a flower pot on to the roof of a car.
Each floor of the apartment building is 2.5m high, the flower pot weighs 1 kg, and the maximum roof load of the car is 50Kg.
Will the flower pot only dent the roof or break it ?
Please show the calculations in your answer.

I have no idea what the answer is, but god I would love to find out what the answer is and how to solve it  :)
Title: Re: Homework Section
Post by: Jubin on February 28, 2009, 11:36:18 pm
Ok, an old one but a good one...
A guy on the 3rd floor of an apartment building drops a flower pot on to the roof of a car.
Each floor of the apartment building is 2.5m high, the flower pot weighs 1 kg, and the maximum roof load of the car is 50Kg.
Will the flower pot only dent the roof or break it ?
Please show the calculations in your answer.
Are those English or American floors? I mean is it 1st,2nd and 3d floor or is it Ground, 1st,2nd and 3d floor? Also only ~50 kg? What is this car made of I ask :)
Though people, come on, answer this question, it is simple physics, pure Mechanics.
Title: Re: Homework Section
Post by: Alsatian on March 01, 2009, 01:23:58 am
I would answer but I havent really began learning physics yet  :(
Title: Re: Homework Section
Post by: Akselbabu on March 02, 2009, 11:31:51 pm
Can you tell me this.

A strange word for Snufs.
Title: Re: Homework Section
Post by: stof on March 03, 2009, 01:22:17 pm
okay...i got an speech i gotta write for school..an argument on why i think the European Culture would be better for Australians then the aboriginal culture (this is from when it was first discovered)..if nobody wants to do it i guess i could always do it myself  :rofl:
Title: Re: Homework Section
Post by: Dmitry on March 03, 2009, 01:25:34 pm
okay...i got an speech i gotta write for school..an argument on why i think the European Culture would be better for Australians then the aboriginal culture (this is from when it was first discovered)..if nobody wants to do it i guess i could always do it myself  :rofl:
You're having a trouble in something here?
Or you just expect someone to make it for you?

The point of this topic is to help, not doing you're homework..
Title: Re: Homework Section
Post by: stiffler2100 on March 04, 2009, 07:51:26 pm
I always had the "I hate school" attitude, but now that Im coming closer and closer to the end of my school life, im starting to realise school is the best time of your life, once its over, you wont see all your friends etc. Everything changes

I hate change  :(

you're soooo right, i used to have a negative attitude towards school, i was actually doing very well until my last year, now I'm not in school anymore life is so boring, it's a huge change and you'll really want to just go back to school and see everyone you knew again :( stay in school for as long as you can, trust me, stay on for 6th form.
Title: Re: Homework Section
Post by: FlameMan on March 04, 2009, 07:58:54 pm
stay in school for as long as you can, trust me, stay on for 6th form.

you can always stop learning, and then do not pass to next class.. thats always few years more in school ^^
Title: Re: Homework Section
Post by: sinamun on March 04, 2009, 09:42:54 pm
ok ok,
i need you to get me 12 pictures that replisent hinduism
and a paragraph explaining each one. i will pay handsomly in argo cash.
Title: Re: Homework Section
Post by: Alsatian on March 04, 2009, 10:58:40 pm
ok ok,
i need you to get me 12 pictures that replisent hinduism
and a paragraph explaining each one. i will pay handsomly in argo cash.

This is for helping with homework, not doing it for you..  :roll:
Title: Re: Homework Section
Post by: Cutt3r on March 05, 2009, 12:52:26 am
ok ok,
i need you to get me 12 pictures that replisent hinduism
and a paragraph explaining each one. i will pay handsomly in argo cash.

Who better to do it than a hindu himself ;) Will help ya out in about 12-13 hours.

EDIT


(http://i42.tinypic.com/28qujop.jpg)

Aum or Om

Om is a sacred symbol for the Hindus. It is placed at the beginning of most Hindu texts as a sacred exclamation to be uttered at the beginning and end of a reading of the Vedas or previously to any prayer or mantra and also is said in the beginning of any puja (religious ritual). According to the Hindu worshippers, Om is the universal name of the Lord.
The term ‘Om’ is said to have a positive effect on the body and mind of the individual chanting it.  There are many ways of writing ‘Om’. In the picture shown above, Om is written in its most recognised form, the Devanagari script.

(http://i40.tinypic.com/2dshli8.jpg)

Hands in prayer

The scope of symbolism is broad and includes physical acts such as offering pranam (obeisances) with folded hands. Such physical gestures tend to induce the appropriate mood and awareness within the practitioner. It is also a form of respectful greeting, a sign of respect for the other person who is being greeted. Hindu people greet each other by placing their two hands together and slightly bowing the head, whilst saying namaste or a similar phrase. They adopt the same posture when greeting the temple deity or a holy person.


(http://i41.tinypic.com/4ujewz.jpg)
The Lotus

The lotus for hindus, is a symbol of purity or transcendence. The lotus is commonly used for sacred rituals in temples or Hindu homes due to its association with purity. The essence of a lotus being symbolic with hindu rituals is because it grows out of mud(considered impure), yet it is beautiful and though it rests on water, it does not touch the water. The essence of the previous sentence is that the Hindus try to be as detached as possible from the impure material life that most people pursue. This does not symbolize that the worshipper will alienate himself from the world. Whatever material items are necessary will be attained(hence the phrase “though it rests on water, it does not touch the water”)


(http://i42.tinypic.com/2wnrb0z.jpg)
The conch

The conch is another symbol and instrument of sacred rituals used mostly in Hindu temples. It is one of the items that one of the Gods of the Holy Trinity, Lord Vishnu, holds in his four hands. This special conch, called the Panchajanya, represents life, as it has come out of life-giving waters. The conch is used as a ceremonial trumpet, as part of religious practices. The conch is sounded during worship at specific points, accompanied by ceremonial bells and singing.


(http://i43.tinypic.com/2dtdv9k.gif)

The Swastika

In Hinduism, the two symbols represent the two forms of the creator god Brahma: facing right it represents the evolution of the universe , facing left it represents the involution of the universe. It is also seen as pointing in all four directions (north, east, south and west) and thus signifies stability and groundedness. Its use as a sun symbol can first be seen in its representation of the god Surya. The swastika is considered extremely holy and auspicious by all Hindus, and is regularly used to decorate items related to Hindu culture. It is used in all Hindu religious designs. Throughout the subcontinent of India, it can be seen on the sides of temples, religious scriptures, gift items, and letterheads.


(http://i43.tinypic.com/ou71y1.jpg)

The Trident(Trishula)

A Trishula is a type of traditional Indian trident, usually a Hindu religious symbol. The trishula is wielded by the Hindu God Shiva. The three points have various meanings and significance. They are most commonly said to represent various trinities--creation, maintenance and destruction and past, present and future. It also represents the place where the three main ‘nadis’, or energy channels meet at the brow.


(http://i40.tinypic.com/2lwm102.jpg)

Circumbulation

Circumbulation is a part of visiting any hindu temple. It symbolizes God being the centre, source and essence of human life and the worshippers recognising this truth. Circumbulation is similar to drawing a circle or a square(the sanctum sanctorum of temples may be circular or in the form of a square). Every point on the circumference of a circle is equidistant from the centre. That is, circumbulation emphasises that no matter who you are, you are equally close to God. 



(http://i39.tinypic.com/nna1ir.jpg)

The Lamp

 In almost every Hindu home and every temple, a lamp is lit daily at the altar of the deity. All auspicious functions commence with the lighting of the lamp which is often maintained right through the occasion. Light symbolizes knowledge, and darkness, ignorance. Knowledge removes ignorance, just as light removes darkness. For Hindus, the light is represents God, who is the source, the enlivener and the illuminator of all knowledge. Hence the lamp is worshipped as God himself.

(http://i40.tinypic.com/167mkud.jpg)


The ‘Aarati’

The aarati is the slow waving of a lighted lamp held in the right hand(sometimes both hands are used) using camphor as the material, in a clockwise direction. When aarati is done, there will be either a silent or loud chant of Hindu mantras or prayers. This holds a spirutual telling significance. Camphor, when lit, burns itself out completely, without a trace. This act signifies that when lit by the fire of knowledge, the ego present in us would burn itself out completely so that we may be one with God.


(http://i44.tinypic.com/9i73io.jpg)

The Tilak

Tilak is a mark of auspiciousness. It is put on the forehead with sandal paste or sacred ashes. The devotees of Siva apply sacred ashes on the forehead and the devotees of Vishnu apply sandal paste. Tilaka is applied at the ‘Ajna Chakra’, the space between the two eyebrows or the ‘seat of thinking’. It has a cooling effect on the person who wears the tilak. Application of sandal paste has great medicinal value, apart from the spiritual influence. Application of sandal paste will nullify the heating effect when you concentrate and work, thus reducing head aches. The tilak is also portrayed as a protection against wrong tendencies and forces.


(http://i44.tinypic.com/153sa4o.jpg)
Application of holy ash

The ash of any burnt object is not regarded as holy ash. Holy ash is the ash obtained from the sacred fire where special wood along with ghee and other herbs is offered as worship to God. The holy ash is generally applied on the forehead, chest, arms etc. Some Hindus also do consume a pinch of the holy ash.
The sacred fire symbolises the surrender of ego and egocentric desires into the flame of knowledge. The ash obtained and when applied, signifies the destruction of evil and remembrance of the divineto the one who applies it. Further it also serves as a reminder to those who see the holy ash that no matter how important they may be, at the end of their life they too would become part of the ash they see, thus reminding them that ego should not find a place in their life.


(http://i42.tinypic.com/2580zmo.jpg)


The Holy Cow, Nandi

Nandi can be found in many hindu temples worldwide. It is a holy bull for the hindus - the vehicle and the flag of Lord Shiva. It is a common sight on  the walls of the Shiva temples. The long past of this emblem will be very evident from the fact that this emblem has been found in the excavations of Harappa Mohanjadaro (the so-called Indus valley civilisation sites). According to Shaivite scriptures the bull represents the dharma (justice).

Title: Re: Homework Section
Post by: sinamun on March 05, 2009, 04:58:44 pm
wow thanks cutter, contact me on msn and well talk :)
i had allready done the homework but yours is much better than my copy and paste :D
Title: Re: Homework Section
Post by: sinamun on March 05, 2009, 08:14:57 pm
ok if you do this for me, i will pay you LOADS!!!!

read this poem and write a 16 line poem in the form of goblin market, so it has to be selling things,

Maids heard the goblins cry:
"Come buy our orchard fruits,
Come buy, come buy:
Apples and quinces,
Lemons and oranges,
Plump unpecked cherries-
Melons and raspberries,
Bloom-down-cheeked peaches,
Swart-headed mulberries,
Wild free-born cranberries,
Crab-apples, dewberries,
Pine-apples, blackberries,
Apricots, strawberries--
All ripe together
In summer weather--
Morns that pass by,
Fair eves that fly;
Come buy, come buy;
Our grapes fresh from the vine,
Pomegranates full and fine,
Dates and sharp bullaces,
Rare pears and greengages,
Damsons and bilberries,
Taste them and try:
Currants and gooseberries,
Bright-fire-like barberries,
Figs to fill your mouth,
Citrons from the South,
Sweet to tongue and sound to eye,
Come buy, come buy."
Title: Re: Homework Section
Post by: Akselbabu on March 05, 2009, 08:18:27 pm
Sorry for asking, but what's up with all these info about hindu?;p
Title: Re: Homework Section
Post by: stiffler2100 on March 05, 2009, 09:10:00 pm
ok if you do this for me, i will pay you LOADS!!!!

read this poem and write a 16 line poem in the form of goblin market, so it has to be selling things,

Maids heard the goblins cry:
"Come buy our orchard fruits,
Come buy, come buy:
Apples and quinces,
Lemons and oranges,
Plump unpecked cherries-
Melons and raspberries,
Bloom-down-cheeked peaches,
Swart-headed mulberries,
Wild free-born cranberries,
Crab-apples, dewberries,
Pine-apples, blackberries,
Apricots, strawberries--
All ripe together
In summer weather--
Morns that pass by,
Fair eves that fly;
Come buy, come buy;
Our grapes fresh from the vine,
Pomegranates full and fine,
Dates and sharp bullaces,
Rare pears and greengages,
Damsons and bilberries,
Taste them and try:
Currants and gooseberries,
Bright-fire-like barberries,
Figs to fill your mouth,
Citrons from the South,
Sweet to tongue and sound to eye,
Come buy, come buy."

what the fuck? you're taking advantage of this whole community, do your own fucking home work -.- this is for help not to get people to do it and you pay them "argo money".
Title: Re: Homework Section
Post by: Jaaskaa on March 05, 2009, 09:59:08 pm
Quote
1. How do politics, preexisting preferences and power negatively affect the group process? What effects have you seen of each of these variables in group decision making? 

I see how preexisting preferences and power can affect directly and indirectly right, this is damn easy. But politics, I don't get it, do they mean politics such as rules and methods and policies  or  do they mean the politic stuffs like Obama, war on iraq and else ?

Thanks.
Title: Re: Homework Section
Post by: Voodoo on March 05, 2009, 10:00:41 pm
I THINK they mean Politics such as rules, methods and policies.
Title: Re: Homework Section
Post by: sinamun on March 05, 2009, 10:11:06 pm
what the f**k? you're taking advantage of this whole community, do your own f**king home work -.- this is for help not to get people to do it and you pay them "argo money".

no im just too lazy to do any poem, since i have no intrest in it why waste my time.
use what you have and take advantage in a good way - George clooney.
Title: Re: Homework Section
Post by: stiffler2100 on March 05, 2009, 11:26:05 pm
no im just too lazy to do any poem, since i have no intrest in it why waste my time.
use what you have and take advantage in a good way - George clooney.

maybe for some education? if you cheat your way through school when you get to the end of it you'll be in the top sets, and actually know nothing, then you'll miserably fail your main test :)
Title: Re: Homework Section
Post by: stof on March 06, 2009, 12:58:50 am
lol thats kinda my problem too atm :D im in tafe now and we needa find out how to do angles...can someone maybe educate me?
Title: Re: Homework Section
Post by: Matthew_Cipricla on March 06, 2009, 01:54:19 am
maybe for some education? if you cheat your way through school when you get to the end of it you'll be in the top sets, and actually know nothing, then you'll miserably fail your main test :)

Ah yeah, you need to know how to do poems to get a great job in this communty dont ya?  :)

Why just today I cheated on a history test. I failzor  :(

And seskom, I will see what I can do on that poem, I got alot of time on my hands....
Title: Re: Homework Section
Post by: stiffler2100 on March 06, 2009, 02:01:29 am
Ah yeah, you need to know how to do poems to get a great job in this communty dont ya?  :)


well, i don't think you understood what i meant, think before you speak, we hardly need anything we learn in school i agree with that, but what your GCSE's show or what ever you get there, it increases your chance of getting a job, your grades count as a lot, so your point is stupid, so yeah, you do need to know how to do poems to get a job in this community somewhat :) as it goes towards your English grade. :D
Title: Re: Homework Section
Post by: Gimli on March 07, 2009, 10:39:07 pm
How many uneven numbers can there be from the number 3694 if the numbers can each only be used once?

The answer is 32... how do I get it? :conf:

Not exactly homework
Title: Re: Homework Section
Post by: Malcolm on March 07, 2009, 10:42:58 pm
maybe for some education? if you cheat your way through school when you get to the end of it you'll be in the top sets, and actually know nothing, then you'll miserably fail your main test :)
Remember kids: It's only cheating if you get caught!

 :razz:
Title: Re: Homework Section
Post by: Chuck_Norris on March 07, 2009, 10:44:29 pm
How many uneven numbers can there be from the number 3694 if the numbers can each only be used once?

The answer is 32... how do I get it? :conf:

Not exactly homework

not sure if its correct but...

3 isn't a even number
6 is a even number (divided by 2 = 3)
9 isn't a even number
4 is a even number (divided by 2 = 2)

3 and 2 = 32 :p

Title: Re: Homework Section
Post by: Cutt3r on March 08, 2009, 06:44:56 pm
The nos 3 and 9 have to be in the units place. So we can interchange the tens, hundreds and thousands place :)

Here we use permutations and combinations. i will tell you what i remember from 9 years ago. Forgive me if it is a lil wrong but I believe you can work the rest out.

Lets start with 2 digit numbers. If 3 is in the units place we can have 3 other numbers (6,9,4) in the tens place. That is 3p1 or 3*2/2*1(3-1=2) = 3---->a

Now we put 9 in the units place. You will get 3 again as above. ---->b

Now we look for 3 digit numbers. We keep 3 in the units place and use a permutation for the tens and hundreds digit numbers. We have 3 other numbers we can use, besides 3. So we use the permutation 3p2 ie 3*2/1 =
6.--->c

Now replace the units digit (3) with 9. Similar to (c) we get 6 again. ---->d

Now we again put 3 in the units place. We use a permutation for the tens, hundreds and thousands place. We have 3 numbers for this and the order matters so the permutation is 3p3 ie 3*2/(3-3)! = 6/1 = 6.---->e

Similarly we get the answer as 6 if we put 9 in the units place.---->f

 Note that 0! and 1! are both = 1.

Now a+b+c+d+e+f = 3+3+6+6+6+6 = 30. So how did Gimli get 32?

Simple. We have not taken the two odd numbers into consideration. 3 and 9 by themselves, as single digits were not taken for the above. Therefore, the final asnwer is 32 :)
Title: Re: Homework Section
Post by: Jubin on March 08, 2009, 09:11:04 pm
cutter, everything is sweet and all, but you start repeating your actions
Quote
Now we look for 3 digit numbers. We keep 3 in the units place and use a permutation for the tens and hundreds digit numbers. We have 3 other numbers we can use, besides 3. So we use the permutation 3p2 ie 3*2/1 =
6.--->c
is actually the same as
Quote
Now we again put 3 in the units place. We use a permutation for the tens, hundreds and thousands place. We have 3 numbers for this and the order matters so the permutation is 3p3 ie 3*2/(3-3)! = 6/1 = 6.---->e
or isn't it?
Title: Re: Homework Section
Post by: Cutt3r on March 09, 2009, 12:54:25 am
Not exactly. In the first quote i was talking about a 3 digit number with '3' in the units place(We keep 3 in the units place and use a permutation for the tens and hundreds digit numbers). Like 643 for example.
In the second quote I am talking about a 4 digit number (We use a permutation for the tens, hundreds and thousands place)like 9463.

However if you are talking about 3p2 and 3p3, the answer to them maybe the same but as i did state, the denominator is 0! and 1!. The denominator is different but both have the same answer ie 1. That is why the answer is 6 in both cases.
Title: Re: Homework Section
Post by: rJCaiG on March 09, 2009, 12:30:33 pm
Could we only ask for help with little parts and not whole assignments? Cheating is not cool....
Title: Re: Homework Section
Post by: Custom on March 18, 2009, 09:38:13 pm
Hello again :)
I am stuck in math :(
I got something about "logistic growth".
I need to know what importance the functions A, B, and C have in the graph (check picture). 
Would really appreciate it if anybody could explain it for me ? :)

Thanks for reading, and for your help :)

Best regards
Custom
Title: Re: Homework Section
Post by: Jubin on March 19, 2009, 01:16:20 am
Hello again :)
I am stuck in math :(
I got something about "logistic growth".
I need to know what importance the functions A, B, and C have in the graph (check picture). 
Would really appreciate it if anybody could explain it for me ? :)

Thanks for reading, and for your help :)

Best regards
Custom
Ok, let's take logically.

First of all the constant C - the bigger is constant C, the bigger is f(x). for example 5/1+a*e^-bx is always bigger then 3/1+a*e^-bx. Take C as the number of cakes you have and (1+a*e^-bx) the number of people on your party. It is logical that the more cakes you have, the bigger slice everybody gets.

Constant A - the bigger is constant A, the more crowded it gets. let's say you always have 5 Cakes( C=5). So the people at first was 2( A=2), equation would be f(x)= 5/1+2*e^-bx. It would be 1+2 people. but now, when we change A bigger, let's say to 3 (A=3) we would get more people, and everybody would get less cake, and someone has to go to store, to get more.

Constant B - The bigger is constant B, the less crowded the place gets. So take B as the constant of farting. The more people fart, the less people stays in the room. In mathematical, let me take only the part of e^-bx. If the B=-7 then -(-7)*x= 7x therefore we get e^7x. If B=0 then -(0)*x=0 therefore we get e^0(=1). If B=7, then -7*x=-7x therefore we get e^-7x = 1/e^7x.

If this is what you asked?
Title: Re: Homework Section
Post by: Cutt3r on March 19, 2009, 01:56:15 am
Jubin is math awesomeness :D the math god :D:D
Title: Re: Homework Section
Post by: Jubin on March 19, 2009, 02:08:02 pm
Jubin is math awesomeness :D the math god :D:D
And the truth is that I am always waiting for mathematicians to solve equations for me.
Title: Re: Homework Section
Post by: Alsatian on March 19, 2009, 11:56:19 pm
My god.. I would expect this is the kind of maths I will be learning soon..  :conf:
Title: Re: Homework Section
Post by: Custom on March 25, 2009, 03:02:02 pm
Hello again
I have some problems with understanding complex numbers..
Pictures uploaded.
And besides the pictures, can somebody proove the following;
Let a be a real number. Evidence that a/i = -ia 
Title: Re: Homework Section
Post by: Jubin on March 25, 2009, 04:41:23 pm
a/i=-ia. Now from the right side take that i to the left side and you get a/(i*i)=-a. We know that i^2= -1 therefore we get a/(-1)=-a => -a=-a. Everything matches don't know any better way to proof it.

 :ps: I am waiting for Ghost to come and say I'm wrong :)
Title: Re: Homework Section
Post by: Matthew_Cipricla on March 26, 2009, 12:09:53 am
Alirhgt Jubin, here is a difficult one (for me atleast). Its not really homework but I would really like to know the answer. How do you solve a rubik's cube with mathemtics? I know it is possible since there is a robot who solves them with mathematic eqoutations. But I am not sure how..... And I am pretty good at algebra too... Do you know the answer? Or like direct me to some other webistes would also be great.
Title: Re: Homework Section
Post by: ~Legend~ on March 28, 2009, 05:54:30 pm
Great idea!!!!
If anyone is stuck on any subjects, please feel free to contact me!  :)
Title: Re: Homework Section
Post by: Kitsune on March 28, 2009, 06:05:21 pm
a/i=-ia. Now from the right side take that i to the left side and you get a/(i*i)=-a. We know that i^2= -1 therefore we get a/(-1)=-a => -a=-a. Everything matches don't know any better way to proof it.

 :ps: I am waiting for Ghost to come and say I'm wrong :)
Nothing wrong here. :P
Title: Re: Homework Section
Post by: Trobby888 on March 29, 2009, 04:57:11 am
Ok. I got a question which I'm having a lot of trouble finding answers to :

Rocket A travels at 4c/5 in a certain direction (c = sped of light). Rocket B travels in the opposite direction of rocket A, at 4c/5. What is the velocity of rocket B relative to A?
Title: Re: Homework Section
Post by: Kitsune on March 29, 2009, 04:58:34 am
If you can explain to me why you can't travel faster then the speed of light, I may be able to find an answer. I think it may have to to with the relativity.
Title: Re: Homework Section
Post by: Trobby888 on March 29, 2009, 05:04:52 am
If you can explain to me why you can't travel faster then the speed of light, I may be able to find an answer. I think it may have to to with the relativity.

Because as you travel towards the speed of light, the factor gamma (gamma = (1-v^2 / c^2)^(1/2)) tends towards 0, so when you have m = m0 / gamma, a divide by 0+ would tend towards infinity, and to make an infinite mass go faster, you need infinite force, which is obviously impossible to archieve. Also,  when you apply more force, a percentage of that force would tend to increase your mass rather than to make you go faster. When your speed tends towards the speed of light, the percentage of the force which increases your mass would tend towards 100%, while the percentage of the force which makes you go faster would tend towards 0%, hence, you don't go faster.
Title: Re: Homework Section
Post by: Kitsune on March 29, 2009, 05:55:13 am
It's all about relativity, which is what I thought initially. Let me put it this way...

I sitting on my chair right now, travelling with basically no speed.  Relative to a fixed point in space I am travelling with no speed, with the speed of the earth's or also with the universe's rotation (if you consider a fixed point in space to be absolutely fixed) and I do not know if anyway has calculated the rotation of the universe relative to a fixed point in further space, but if it existed, I doubt it would be anywhere close to the speed of light. Now, if I then consider my speed relative to the light bouncing off the walls around me, I am travelling at the speed of light and I have this incredible mass. So, relative to light, anyone ravelling faster then no speed, is travelling faster then the speed of light. This shows that these laws in physics, cannot apply to such relative speed, but only to a fixed point.

If a that's a mouthful, then here's a simpler example...

You want relative speed? Why not compare the speed of light in one direction against the speed of light in another direction (because light travels in all directions)? That makes their relative speed twice the speed of light. Think about this and you will realise that you must compare speed to an absolutely fixed point in space when using such concepts in physics.

Now I am cannot say for certain where such places exist (though I would assume it is in the regions, which are not occupied by universes, assuming universes do not move, otherwise it would just be some point in our universe's space), but it seems obvious to me that there exist these constraints with regard to what you consider as travelling faster then the speed of light and defying physics.

I could be completely wrong but this seems like the most logical, so if someone can explain more correctly, please do! ^^

/me wonders when Jubin will check the topic...
Title: Re: Homework Section
Post by: Kitsune on March 29, 2009, 06:13:22 am
Another point is that if you were to argue that relatively, an object being compared to the speed of light is not travelling faster then it, you may not be defying some laws of physics, but you are defying others with regard to calculations involving relative speed. I have never heard of any such exceptions for these calculations, so if you really think it is so, I would be glad to hear how you can explain this.

You're explanation to why you can't travel faster than the speed of light is not detailed enough to help me. You need to explain the why of your why if it is to be of any help, but that's not needed atm as I would rather get something to contradict my theory (unless it involves explaining the why of your why).

why of your why = explain the explanation o_O

I just realised that even if I consider something out of our universe, relative to here if you consider other factors with the earth's speed with the light travelling, maybe that because faster then the speed of light. So my main issue is, what is a fixed point in space?

Someone please explain this before I go mad!!!
Title: Re: Homework Section
Post by: Kitsune on March 29, 2009, 09:32:14 am
How did you calculate that?

I read Wikipedia and everything makes sense now. Apparently the conventional speed formula becomes less accurate at speeds approaching the speed of light, which is where another equation (that I didn't know about) comes in.

Why didn't they teach this in my high school physics? >.<
Title: Re: Homework Section
Post by: Jubin on March 29, 2009, 09:46:24 am
sry the answer is 292 000 km/s. Equation is u=(v1+v2)/(1+(v1*v2/c^2)) where v1 is speed of the first body, v2 speed of the second body. c- speed of light and u is relative speed.
Title: Re: Homework Section
Post by: Kitsune on March 29, 2009, 09:51:39 am
Yeah, that's what I got.
Title: Re: Homework Section
Post by: Trobby888 on March 29, 2009, 10:09:34 am
It's all about relativity, which is what I thought initially. Let me put it this way...

I sitting on my chair right now, travelling with basically no speed.  Relative to a fixed point in space I am travelling with no speed, with the speed of the earth's or also with the universe's rotation (if you consider a fixed point in space to be absolutely fixed) and I do not know if anyway has calculated the rotation of the universe relative to a fixed point in further space, but if it existed, I doubt it would be anywhere close to the speed of light. Now, if I then consider my speed relative to the light bouncing off the walls around me, I am travelling at the speed of light and I have this incredible mass. So, relative to light, anyone ravelling faster then no speed, is travelling faster then the speed of light. This shows that these laws in physics, cannot apply to such relative speed, but only to a fixed point.

If a that's a mouthful, then here's a simpler example...

You want relative speed? Why not compare the speed of light in one direction against the speed of light in another direction (because light travels in all directions)? That makes their relative speed twice the speed of light. Think about this and you will realise that you must compare speed to an absolutely fixed point in space when using such concepts in physics.

Now I am cannot say for certain where such places exist (though I would assume it is in the regions, which are not occupied by universes, assuming universes do not move, otherwise it would just be some point in our universe's space), but it seems obvious to me that there exist these constraints with regard to what you consider as travelling faster then the speed of light and defying physics.

I could be completely wrong but this seems like the most logical, so if someone can explain more correctly, please do! ^^

/me wonders when Jubin will check the topic...

Those formula apply for if there was an object stationary relative to the universe, it would observe an object moving at high speeds, and see it with m = m0 / gamma, t = t0 * gamma and so on. But for a person sitting in that fast moving object, it won't detect any of this. It would still see everything on the ship to be the same. That also explains why a person in a ship going at, say c-1 ms-1, could skip generations of life, due to time dialation.

You included the concept of twin paradox there, Ghost. The truth in the twin paradox is that, while both objects may see each other going younger, and all those relativity things, it is the actual moving object relative to the universe which is suffering the relativity consequences.

Also, light is always travelling at c, from anyone's frame of reference, even on someone who's travelling fast. According to your explanation, you are saying that if there was an object going at c/4, if a electromagnetic signal (same concept as light) goes to that object, it should arrive at the ship at (c - c/4) = 3c/4 ms-1. Sorry, but that's the wrong concept. When the light arrives, it should be c, no matter what.

sry the answer is 292 000 km/s. Equation is u=(v1+v2)/(1+(v1*v2/c^2)) where v1 is speed of the first body, v2 speed of the second body. c- speed of light and u is relative speed.

Ok. I got 40c/41, which is the equilivant to 292682926.8ms-1.
Title: Re: Homework Section
Post by: Kitsune on March 29, 2009, 10:11:37 am
Yeah, if only the Australian (Western) education system decided to do something more decent, I wouldn't have to think so hard to come up with useless logic. = ="""""""""
Title: Re: Homework Section
Post by: ~Legend~ on March 29, 2009, 02:42:53 pm
Remember kids: It's only cheating if you get caught!

 :razz:
 

Better not be a bad influence to younger children!   ;)
Title: Re: Homework Section
Post by: Voodoo on March 29, 2009, 02:47:20 pm
Better not be a bad influence to younger children!   ;)
Too late.
Title: Re: Homework Section
Post by: ~Legend~ on March 29, 2009, 06:40:51 pm
Too late.


Oh well,
At least we tried (:trust:)
Title: Re: Homework Section
Post by: WBlastRose on March 30, 2009, 02:13:29 pm
Here's my homework: Stay home for 2 weeks, eat donuts, play Wii, play GTA SA:MP, and stay up untill 6 A.M!
Title: Re: Homework Section
Post by: 9r2e5i3k on March 30, 2009, 02:49:17 pm
Here's my homework: Stay home for 2 weeks, eat donuts, play Wii, play GTA SA:MP, and stay up untill 6 A.M!
Can I help you out with that? :lol:
Title: Re: Homework Section
Post by: WBlastRose on March 30, 2009, 03:08:50 pm
Can I help you out with that? :lol:
Sure! . Bring a bucket of popcorn to my house and a large Coca-Cola! .
Title: Re: Homework Section
Post by: ~Legend~ on March 30, 2009, 11:09:53 pm
Here's my homework: Stay home for 2 weeks, eat donuts, play Wii, play GTA SA:MP, and stay up untill 6 A.M!


6 AM? WOW!
How long will you sleep for :eek:
The most I have done (on my own without friends) is like 3 AM!

:ps: Do you want any chips with that popcorn?
Title: Re: Homework Section
Post by: WBlastRose on March 31, 2009, 12:49:32 pm


6 AM? WOW!
How long will you sleep for :eek:
The most I have done (on my own without friends) is like 3 AM!

:ps: Do you want any chips with that popcorn?
I sleep, like, till 10 A.M maxium, but that's because im on Spring Break!  :rofl: :rofl: :rofl: In school time I go to sleep at 1 A.M .
Title: Re: Homework Section
Post by: stiffler2100 on April 02, 2009, 01:35:52 pm


6 AM? WOW!
How long will you sleep for :eek:
The most I have done (on my own without friends) is like 3 AM!

:ps: Do you want any chips with that popcorn?

wow...let's make this a who stays up the longest competition, i usually don't sleep for 2 days then when i do sleep i sleep for about 8 hours:P
Title: Re: Homework Section
Post by: tiderman on April 02, 2009, 04:38:03 pm
wow...let's make this a who stays up the longest competition, i usually don't sleep for 2 days then when i do sleep i sleep for about 8 hours:P
LOL, when I stayed up two days after a LAN party I slept for 16 hours. Was tired when I woke up, though. Too bad.
Title: Re: Homework Section
Post by: ~Legend~ on April 04, 2009, 07:14:49 pm
I sleep, like, till 10 A.M maxium, but that's because im on Spring Break!  :rofl: :rofl: :rofl: In school time I go to sleep at 1 A.M .


Woo! Same, I just started my holz..
Title: Re: Homework Section
Post by: Jubin on October 18, 2009, 11:08:17 pm
Just bumping up this topic, as I think a lot of us, have forgotten about it.
Title: Re: Homework Section
Post by: Billy_Hobo on October 19, 2009, 03:10:41 am
I need help with JAVA assignment, who has knowledge?

ANd... WHo can speak fluent french?
Title: Re: Homework Section
Post by: Quang on October 20, 2009, 09:12:06 am
I need some help with The Kite Runner... anyone read the book and remember anything? please add me on msn because its alot of questions :D

I will pay you 10k if you manage to finish half of the work... I think.
Title: Re: Homework Section
Post by: ~Legend~ on October 20, 2009, 10:37:40 am
I need help with JAVA assignment, who has knowledge?

ANd... WHo can speak fluent french?


I can't speak fluent French, but I could help you a tiny bit.... still learning French meh!

I need some help with The Kite Runner... anyone read the book and remember anything? please add me on msn because its alot of questions :D

I will pay you 10k if you manage to finish half of the work... I think.


Cheeky, do you're own work, tehe.
There's a movie based on that book, watch that and see if you can gain anything else, haha
Title: Re: Homework Section
Post by: Quang on October 20, 2009, 03:40:06 pm
I can't speak fluent French, but I could help you a tiny bit.... still learning French meh!
 

Cheeky, do you're own work, tehe.
There's a movie based on that book, watch that and see if you can gain anything else, haha


These questions are questions I cant find in the movies, and I hate reading book... but allright, I will do my own work then...
Title: Re: Homework Section
Post by: rJCaiG on October 22, 2009, 09:10:57 am
I need the answer to a maths question in the next 3 hours if possible,
What is the volume of a rectangular prism in which the length, breadth and height add to 20cm and the sides are integral?

Note: Integral apparently means whole number. Do NOT reply if you are not 100% sure!!!!
Title: Re: Homework Section
Post by: ~Legend~ on October 26, 2009, 05:11:41 pm
These questions are questions I cant find in the movies, and I hate reading book... but allright, I will do my own work then...


Good boy  :lol:

Note: Integral apparently means whole number. Do NOT reply if you are not 100% sure!!!!


I think you mean "integer". An integer is any positive or negative whole number, i.e. not in the format of fractions, decimals or SURDs.  :)
Title: Re: Homework Section
Post by: ShawmMoe on October 27, 2009, 04:59:41 pm
Got problems with this one.. Not sure about it.. Please help :) Picture uploaded ;)
Title: Re: Homework Section
Post by: Kitsune on October 27, 2009, 05:15:05 pm
Got problems with this one.. Not sure about it.. Please help :) Picture uploaded ;)
Initial equation:
(2ac)3b54(ab)2
(ba2)2

Rearranged to a more proper format:
4b5(2ac)3(ab)2
(2ab)2

Brackets expanded:
4b523a3c3a2b2
22a2b2

Grouped like types:
32a5b7c3
4a2b2

Canceled out values:
8a3b5c3
Title: Re: Homework Section
Post by: Jubin on October 27, 2009, 06:04:42 pm
Typical asian : ))
But one of the few Argonather, who doesn't make me lose all hope in the humanity.
Title: Re: Homework Section
Post by: Quang on October 30, 2009, 06:48:36 pm
Typical asian : ))

Im no typical asian, I suck at math xD
Title: Re: Homework Section
Post by: ShawmMoe on November 22, 2009, 02:28:07 pm
Math question. Picture uploaded. Please explain how I can find the answer...
Title: Re: Homework Section
Post by: Jubin on November 22, 2009, 02:48:20 pm
well first thing I noticed is that 2a/(4b+2a) is actually 2a/2(2b+a) => a/2b+a but hey now you have (3a-a)/(2b+a) = 2a/2b+a

EDIT: picture added
Title: Re: Homework Section
Post by: 9r2e5i3k on November 24, 2009, 07:52:46 am
well first thing I noticed is that 2a/(4b+2a) is actually 2a/2(2b+a) => a/2b+a but hey now you have (3a-a)/(2b+a) = 2a/2b+a

EDIT: picture added

is it legal to do this?
2a1 / 2b + a1 =

2  / 2b + 1 =

b + 1/2
Title: Re: Homework Section
Post by: Kitsune on November 24, 2009, 09:49:32 am
is it legal to do this?
2a1 / 2b + a1 =

2  / 2b + 1 =

b + 1/2
First off, if you want to to divide the equation by 'a', then you need to include an equality, and do the same on the other side of the equation, so that it balances out. Otherwise, the most you can do is take a factor of 'a', but the 'a' would still exist, so your second equation should actually look like 'a(2/(2b)+1)'.

Secondly, I see that you've turned, '2/(2b)+1', into 'b+1/2'. I don't see how you figured that out, but it isn't a valid conversion.
Title: Re: Homework Section
Post by: Jubin on November 25, 2009, 10:42:40 am
is it legal to do this?
2a1 / 2b + a1 =

2  / 2b + 1 =

b + 1/2
so in otherwords of Kitsune's text - no it's illegal and you should be suspected.
Well lets assume, that a= 3 and b=2. at first you have 2*1/(2*2+1) = 3/7  after the first you got 2/2b+1 which is 2/5 and 3/7 does not equal to 2/5
Title: Re: Homework Section
Post by: Melvin on November 25, 2009, 09:46:02 pm
so in otherwords of Kitsune's text - no it's illegal and you should be suspected.
Well lets assume, that a= 3 and b=2. at first you have 2*1/(2*2+1) = 3/7  after the first you got 2/2b+1 which is 2/5 and 3/7 does not equal to 3/7

Congratulations, You just brought me some Headache :O
Title: Re: Homework Section
Post by: Gerrie = Banned (Daco) on November 27, 2009, 06:00:50 pm
Questions please. :D
Title: Re: Homework Section
Post by: Yihka on November 29, 2009, 03:35:08 pm
Uhm

Why do you all say it so hard? O.o

a2 + b1
a2 + b2

See it like this

a2 + b1                            a2+b2

A = Apple b = bean

So the firstp erson has 2 apples and 1 bean

The other guy has 2 apples and 2 beans.

a2 + b1                           a2+b2
-a2                                 -a2

You begin getting the apples away. They both have the same amount.

You get:

b1                                 b2
-b1                                -b1

You get 1 bean away, because you can at both.

What do you get?

b1.



But I forgot what you have to do afterwards...
But maybe that is something else... lol..
Title: Re: Homework Section
Post by: ShawmMoe on December 01, 2009, 07:53:08 am
What about this one:

Santa Claus has a pair of trousers on. The trousers is held up by a belt.
Santa Claus likes good food and Christmas parties and expect to take at 3 cm in thickness, diameter.
How many holes must be enlarged to their belts over the festive season when there is 2.5 cm
between the holes?
Title: Re: Homework Section
Post by: Jubin on December 01, 2009, 08:17:14 am
Answer: none - Santa Claus just takes his pants off.
Title: Re: Homework Section
Post by: Gerrie = Banned (Daco) on December 01, 2009, 02:40:01 pm
Answer: none - Santa Claus just takes his pants off.

Yup, tricky question.
Title: Re: Homework Section
Post by: ShawmMoe on December 01, 2009, 03:55:08 pm
LOL it's really a math question... There is an answer existing, WITH NUMBERS...
Title: Re: Homework Section
Post by: Jubin on December 01, 2009, 04:34:43 pm
Real answer should be 4. Though I would still suggest Santa to take his pants off.
Title: Re: Homework Section
Post by: Quang on December 01, 2009, 08:48:22 pm
Real answer should be 4. Though I would still suggest Santa to take his pants off.

I like the way you think, rawr...
Title: Re: Homework Section
Post by: ShawmMoe on December 05, 2009, 02:49:30 pm
Answer was correct, thanks Jubin :)
Got another question actually...
How do I calculate what the actual consentration of [CH3COOH] is?
Thanks for taking your time to read.
-ShamMoe   
Title: Re: Homework Section
Post by: Jubin on December 05, 2009, 04:09:21 pm
Answer was correct, thanks Jubin :)
Got another question actually...
How do I calculate what the actual consentration of [CH3COOH] is?
Thanks for taking your time to read.
-ShamMoe   
Well you need to know how much you have dilution  and how much in it there is CH3COOH and then divide the two. For example if I got 100 g of dilution and in it I got 25g of CH3COOH then 25/100 = 0,25 or 25%
Title: Re: Homework Section
Post by: ShawmMoe on December 05, 2009, 04:14:04 pm
I have 9 different dilutions. The first one is with 1 ml of CH3COOH, and 99 ml of water, the actual concentration of that would be...?
Title: Re: Homework Section
Post by: Jubin on December 05, 2009, 09:22:39 pm
Well here you have concentration by litres. You got 1 ml of CH3COOH and 99 ml of water. So together you have 1ml+99ml= 100ml of dilution. In it there is 1ml of CH3COOH so 1ml/100 ml = 0,01 = 1%
Title: Re: Homework Section
Post by: ShawmMoe on December 05, 2009, 09:34:32 pm
Okay. What about this:
H2(g) + I2(g) <-> 2HI(g)                                       Kc = 54.4                                               (temperature: 424,4 Celcius)
An equilibrium contains 0.01767M HI, and 0.00313M I2, and it's pushed out of equilibrium by the concentration of H2, which is increased to 0.00600M.
What we need to calculate here, is the participants' reaction concentration when equilibrium has nominated again.
Thanks so far :)
Title: Re: Homework Section
Post by: Jubin on December 06, 2009, 04:09:40 pm
Chemistry ain't really my strong point. So can't help you out in there.
Title: Re: Homework Section
Post by: ShawmMoe on December 06, 2009, 04:11:06 pm
Ok. Will wait, maybe someone else have the answer :)
Title: Re: Homework Section
Post by: Amon Ra on December 06, 2009, 04:21:46 pm
Okay. What about this:
H2(g) + I2(g) <-> 2HI(g)                                       Kc = 54.4                                               (temperature: 424,4 Celcius)
An equilibrium contains 0.01767M HI, and 0.00313M I2, and it's pushed out of equilibrium by the concentration of H2, which is increased to 0.00600M.
What we need to calculate here, is the participants' reaction concentration when equilibrium has nominated again.
Thanks so far :)

ShawMoe, all I can say is, I can solve that question, but it seems that you have some missing data there, either that or I am not capable of answering that question.
Title: Re: Homework Section
Post by: Roman on December 06, 2009, 04:26:05 pm
Alright...I kinda like this topic cause I seems i need a help with my biology homework too :)
Who knows how to solve that stupid questions? I think it is DNA in de cell, but I dont know what lines are related to?

PLease who knows help answer this. But if you dont know and just trying to write something - dont do it..
alright, here we are:



(http://i49.tinypic.com/15pq3ys.jpg)

Post Merge: December 07, 2009, 05:18:25 am
omg does anybody knows how to answer this?
Title: Re: Homework Section
Post by: 9r2e5i3k on December 07, 2009, 08:48:30 am

Post Merge: December 07, 2009, 05:18:25 am
omg does anybody knows how to answer this?
Tried searching on Wikipedia? I bet that stuff is there.

I knew that like 2 years ago, but I forgot  :razz:
Title: Re: Homework Section
Post by: Gerrie = Banned (Daco) on December 07, 2009, 07:34:03 pm
(http://i47.tinypic.com/2iabzbl.jpg)

Jubin ?
Title: Re: Homework Section
Post by: ShawmMoe on December 12, 2009, 09:41:23 pm
Aight. Let's get back to my first question... Asked the teacher about your theory, turned out that it was wrong, m8 :(
I have calculated the formal concentration, and I need the actual concention (maybe there exist some kind of a formula)?
Please, I need this ASAP.
Thanks again :)
Title: Re: Homework Section
Post by: Jubin on December 12, 2009, 11:32:57 pm
(http://i47.tinypic.com/2iabzbl.jpg)

Jubin ?
5/0 -> plus infinity?
Title: Re: Homework Section
Post by: ShawmMoe on December 15, 2009, 03:51:09 pm
I need an answer ASAP for this! Very very very important! Going to hand in my biggest assignment made every tonight! Need to answer this final question;
How can you rewrite Ks, so that you can calculate pH using Ks?
I really need an answer of this, and the one who finds me the answer will get a reward; 90K SA:MP money.
please answer ASAP.
Thanks.
Title: Re: Homework Section
Post by: Brad. on December 15, 2009, 04:30:38 pm
I need an answer ASAP for this! Very very very important! Going to hand in my biggest assignment made every tonight! Need to answer this final question;
How can you rewrite Ks, so that you can calculate pH using Ks?
I really need an answer of this, and the one who finds me the answer will get a reward; 90K SA:MP money.
please answer ASAP.
Thanks.

This is copied out of one of my old e-text books - hope it helps you:

[code]
The pH of a solution depends on the concentration of H+(aq) ions present.

A shorthand method of denoting concentration of hydrogen ions is [H+(aq)]. The square brackets surrounding the ion symbol mean 'concentration in moles per litre'.

When the concentration of hydrogen ions is expressed using powers of 10, the pH is equal to the negative of the power number.
Example:

[H+(aq)] = 0.01 mol l-1 = 10-2 mol l-1

So in the example above, the pH = 2. This is because the concentration of H+ ions are expressed as a power of 10, where the power is -2.

The exact pH of a solution can be calculated using:

    pH = -log[H+(aq)]

For most solutions the pH lies in the range 0 to 14.
Example:

In a solution of pH 2, what is the concentration of H+(aq)?

pH of solution = 2

[H+(aq)] = 10-2 mol l-1
Example:

A salt solution has a hydrogen ion concentration of 10-9 mol l-1. What is its pH?

[H+(aq)] = 10-9 mol l-1

pH of solution = 9

Calculations involving the ionic product

In pure water the concentration of hydrogen ions is equal to the concentration of hydroxide ions.

The pH of pure water is 7.

This means that the concentrations of both the hydrogen and hydroxide ions are 10-7 mol l-1.

This is written:

[H+(aq)] = [OH-(aq)] = 10-7 mol l-1

Multiplying the concentration of hydrogen ions and the concentration of hydroxide ions gives the ionic product for water:

[H+(aq)]
Title: Re: Homework Section
Post by: Gerrie = Banned (Daco) on December 16, 2009, 11:29:38 am
5/0 -> plus infinity?

Yeah. :)
Title: Re: Homework Section
Post by: Janar on December 19, 2009, 08:33:59 pm
Word 'dye', how is that written in Present Continuous?
As word 'die' is 'dying' in Present Continuous.
According to the -ing end rules, it should by 'dying' also.
Can someone confirm this? My English teacher didn't know this either.
Title: Re: Homework Section
Post by: Jubin on December 19, 2009, 09:13:19 pm
Dyeing:
the use of dye to change the color of something permanently
http://wordnetweb.princeton.edu/perl/webwn (http://wordnetweb.princeton.edu/perl/webwn)
Title: Re: Homework Section
Post by: Janar on December 20, 2009, 08:28:40 pm
Okay, thanks!
Title: Re: Homework Section
Post by: ShawmMoe on January 12, 2010, 09:16:38 am
Math question to Jubin :)
Pictures uploaded..
You know what to do on the first one..
Second: Calculate using the square of a two-size.
Third and last: Calculate using two square sum multiplied with two-size difference..
(Sorry for my english)..
Title: Re: Homework Section
Post by: Jubin on January 13, 2010, 09:46:53 am
Dude, those are way too easy, so why won't you at least try to do them yourself, and post a picture of your calculation I can tell you what you did wrong ( if you did something wrong)
Title: Re: Homework Section
Post by: Nighteyes on January 13, 2010, 01:55:12 pm
Wow, never learned the -21 (x) bla..blaa, this really hard, tho.
Title: Re: Homework Section
Post by: ShawmMoe on January 13, 2010, 03:02:24 pm
Ok..
Here we go:
The first one: You showed me how to do it when it's -, and I understood it, but dunno when it's +.. And yes, I tried, I always get a different answer than my calcuator...
Uploaded picture of the 2nd and 3rd.
Thanks in advance.
Title: Re: Homework Section
Post by: Jubin on January 13, 2010, 03:19:22 pm
2nd it should be +25T2

 and 3d is correct.
Title: Re: Homework Section
Post by: ShawmMoe on January 13, 2010, 03:22:24 pm
May I ask, how do I know when I shall use + or - in such case?
Title: Re: Homework Section
Post by: Jubin on January 13, 2010, 06:33:29 pm
May I ask, how do I know when I shall use + or - in such case?
well (a+b)2=a2+2ab+b2
and (a-b)2=a2-2ab+b2

so if you see + inside of the brackets it will be +
and if you see - inside of the brackets it will be -
Title: Re: Homework Section
Post by: ShawmMoe on January 14, 2010, 11:32:48 am
Oh I see.. Now it makes much more sence.
Bur what about the 1st math question? The one I didnt know how to solve...
Calcuator gives a different answer than mine.. A whole different.
Title: Re: Homework Section
Post by: Jubin on January 14, 2010, 01:32:10 pm
Well first of all, let's say a=2 and b=3 there fore we get [(3*2)/(2*3+2)]+[(2*2)/(4*3+2*2)]= 1 so whatever we do with later, it all still must equal to 1.

Let's take the 2a/4b+2a, well there we can see that it is 2a/2(2b+a) because 2(2b+a)= 4b+2a. So 2a/2(2b+a) is equaled to a/2b+a

Now we have (3a/2b+a) +(a/2b+a) as the denominator is the same (2b+a) we can write it on the same fraction

so it will be (3a+a)/(2b+a) = 4a/2b+a that should be all, now let's see if the test goes right. 4*2/2*3+2= 8/8= 1
Whoa, test comes out, therefore 4a/2b+a is the right answer.
Title: Re: Homework Section
Post by: ShawmMoe on January 14, 2010, 03:00:41 pm
Ok. I get it, there wont come any further questions in those kinda questions. I understand them now :) So thanks man :)
Title: Re: Homework Section
Post by: Lionel Valdes on January 14, 2010, 10:54:31 pm
11,5x100= ?
Title: Re: Homework Section
Post by: Jubin on January 14, 2010, 11:02:41 pm
11,5x100= ?
(http://www.joeschmidt.com/img/einstein-google.jpg)
Title: Re: Homework Section
Post by: ShawmMoe on January 31, 2010, 07:24:16 pm
Need someone who is good at Deutch... Try to correct these 2-3 sentences, edit them as you like, just make them sound like they make sence :) And please, DON'T USE AN ONLINE TRANSLATER!
Wenn er sich in diese ummbekannte Welt, er die Karte folgte, stand er bei der Kreuzung nach der Karte. Es gab sogar ein Schl
Title: Re: Homework Section
Post by: Janar on May 07, 2010, 12:57:50 pm
I need to find a music video for Monday.
The music video's lyrics must describe some global problem(Food Insecurity, poverty, war etc).

Could you help me finding one?

And not 'Big Yellow Taxi' song, teacher showed that one already and said it is not allowed.
Title: Re: Homework Section
Post by: 9r2e5i3k on May 07, 2010, 03:27:22 pm
I need to find a music video for Monday.
The music video's lyrics must describe some global problem(Food Insecurity, poverty, war etc).

Big Cyc - Makumba

Shows the problem of racism in Poland (but the problem is global I guess). Lyrics are in polish though.
Title: Re: Homework Section
Post by: rJCaiG on May 07, 2010, 03:33:39 pm
Bliss n eso - The sea is rising
Title: Re: Homework Section
Post by: Jubin on May 08, 2010, 10:17:10 pm
I need to find a music video for Monday.
The music video's lyrics must describe some global problem(Food Insecurity, poverty, war etc).

Could you help me finding one?

And not 'Big Yellow Taxi' song, teacher showed that one already and said it is not allowed.
YouTube - Broadcast Yourself. (http://www.youtube.com/watch?v=LzpTmcq7nBg#)

Anti-Flag - One Trillion Dollars (http://www.dailymotion.com/video/x3ulbb)

Basically your teacher want you to study my music taste : )
Title: Re: Homework Section
Post by: Janar on May 09, 2010, 09:11:30 pm
Thanks.
These songs are great, I loved them.
Let's see tomorrow, what my teacher will say about it.
Title: Re: Homework Section
Post by: Gimli on October 04, 2010, 05:15:49 pm
Anyone have any ideas?


(http://i51.tinypic.com/idhw0n.png)
Title: Re: Homework Section
Post by: ~Legend~ on October 04, 2010, 06:42:43 pm
Anyone have any ideas?


(http://i51.tinypic.com/idhw0n.png)

I have a few ideas, for the top two sequences, but I what I find annoying is that although they seem to work, they do not fit the sequence rule (which is important, in this case).

For the third puzzle, if you notice, for example - the top of that M (first in sequence) forms the bottom of the heart, and likewise, all of them have a similar link.
Title: Re: Homework Section
Post by: Gimli on October 04, 2010, 06:44:26 pm
Thanks a lot for your reply mate. Hmm.. look at the form of the letters, there aren't any curves in the forms. Can this be related in any way? :conf:
Title: Re: Homework Section
Post by: Witchking on October 04, 2010, 07:18:07 pm
The one line at Top gimli is like this i think


1 - 1 - 3 - 9 - 27 =81

Well every time you move to the right in the list you multiply by 3

1x3 = 3

1x3=3

3x3 =9

9x3=27

27x3=81
Title: Re: Homework Section
Post by: ~Legend~ on October 04, 2010, 07:35:52 pm
Thanks a lot for your reply mate. Hmm.. look at the form of the letters, there aren't any curves in the forms. Can this be related in any way? :conf:

Not a problem. I only had a very quick look at it earlier on. The curves - nice idea, but I don't think there are very many letters with curves in - only C, D... etc.
It could be a possibility, but there must be a way of figuring out exactly the sequence rule (or mathematically, the nth term).

The one line at Top gimli is like this i think


1 - 1 - 3 - 9 - 27 =81

Well every time you move to the right in the list you multiply by 3

1x3 = 3

1x3=3

3x3 =9

9x3=27

27x3=81

I also tried that, but that was one of the ones I found the rule did not work equally for all terms. For instance, the first 1 - Tand, any ideas what significance this has? Plus, might just be me being over suspicious, but I thought that was a too straight forward in comparison to the other two. But who knows? Maybe there is something to do with triangle numbers (if you remember what they are).

P.S. Tand, relating to your signature, I believe that I, am Legend.  :D
Title: Re: Homework Section
Post by: Gimli on October 04, 2010, 08:13:43 pm
Not a problem. I only had a very quick look at it earlier on. The curves - nice idea, but I don't think there are very many letters with curves in - only C, D... etc.
It could be a possibility, but there must be a way of figuring out exactly the sequence rule (or mathematically, the nth term).

Thanks guys.

Look at how the letters change too - each one is somehow related to the previous one (in terms of shape), e.g. there's an L in the A, etc.

Tandtrollet, I tried that too, but I can't seem to figure out how the very first 1 appears..
Title: Re: Homework Section
Post by: Witchking on October 04, 2010, 08:33:45 pm

Tandtrollet, I tried that too, but I can't seem to figure out how the very first 1 appears..


Let's first look at an example. Let's look at the list of numbers

                                   3^1, 3^2, 3^3, 3^4, ....   
Finding the actual values, we get    3,   9,  27,  81,  ....


So what is the pattern in the bottom sequence? Well, every time you move to the right in the list you multiply by 3, and every time you move to the left in the list you divide by 3. So we could take the bottom sequence and keep going to the left and dividing by 3, and we'd have the sequence that looks like this:

..., 3^-3, 3^-2, 3^-1, 3^0, 3^1, 3^2, 3^3, 3^4, ....     

..., 1/27,  1/9,  1/3,   1,   3,   9,  27,  81,  ....


So now we know what all the powers of 3 are! Actually, we just did the integer powers of 3. But that's probably enough for now.


While the above argument might help convince your intuitive side that any number to the zero power is 1, the following argument is a little more rigorous.

This proof uses the laws of exponents. One of the laws of exponents is:

   n^x
   --- = n^(x-y)
   n^y   

for all n, x, and y. So for example,

   3^4
   --- = 3^(4-2) = 3^2
   3^2


   3^4
   --- = 3^(4-3) = 3^1
   3^3
   

Now suppose we have the fraction:

    3^4
    ---
    3^4

This fraction equals 1, because the numerator and the denominator are the same. If we apply the law of exponents, we get:

       3^4
   1 = --- = 3^(4-4) = 3^0
       3^4

So 3^0 = 1.

We can plug in any in number in the place of three, and that number raised to the zero power will still be 1. In fact, the whole proof works if we just plug in x for 3:

                  x^4
  x^0 = x^(4-4) = --- = 1
                  x^4       


\k thx bye  :)
Title: Re: Homework Section
Post by: Gimli on October 04, 2010, 09:24:55 pm
Hmm, thanks for the explanation, but... there are two ones, only out of which one is accounted for. What causes the other one to appear? Logically there should only be a single one, right? :conf: 

1 = ?
1 = 3^0
3 = 3^1
9 = 3^2
27 = 3^3
81 = 3^4
Title: Re: Homework Section
Post by: Kitsune on October 04, 2010, 10:12:01 pm
The sequence is 3(1/2)(n-2)(n-1-|n-2|+|n-1-|n-2||) with n starting at 1.
Title: Re: Homework Section
Post by: Gimli on October 04, 2010, 10:29:19 pm
The sequence is 3(1/2)(n-2)(n-1-|n-2|+|n-1-|n-2||) with n starting at 1.

Nice answer! Could you post the solution too? :)
Title: Re: Homework Section
Post by: Kitsune on October 04, 2010, 11:21:55 pm
It's a little complicated to try and explain the exact process I went through in a non-ambiguous manor, but I'll see if I can come up with something.
Title: Re: Homework Section
Post by: ~Legend~ on October 05, 2010, 01:26:46 am
Wow, seen some very different methods today, which I haven't yet learned.
I am not sure what the question is asking with giving the explanation - I would presume it would be the nth term rule, but that again depends on the context, I suppose.
Title: Re: Homework Section
Post by: Kitsune on October 05, 2010, 07:23:51 am
In attempting to explain my solution, I ended up getting a different answer. Both answers work, but this one just happens to be somewhat simpler. This reiterates that fact that my process doesn't follow an exact convention, and due to the nature of this, it is far from the only solution to the sequence, and by playing around with equations, you might even be able come up with a different number to finish the sequence. With all that in mind, my new solution is given below:

(http://img529.imageshack.us/img529/7556/sequence.jpg) (http://img529.imageshack.us/img529/7556/sequence.jpg)
(Click on image for full scale)

If you don't understand how I came up with a specific equation within the solution, I can explain in further detail.
Title: Re: Homework Section
Post by: LoCoMoToR on October 05, 2010, 07:42:07 am
omg amazing topic! great fcking community we got here!!! :D:D:D:D
sorry just had to post. in case that later on i need help and can't find the topic.
Title: Re: Homework Section
Post by: Kitsune on October 05, 2010, 09:05:37 am
I would presume it would be the nth term rule, but that again depends on the context, I suppose.
Context is irrelevant. As long as you're able to produce a valid equation for the pattern of the sequence, there's nothing anyone can say to reject your result.
Title: Re: Homework Section
Post by: ~Legend~ on October 05, 2010, 11:29:04 pm
Context is irrelevant. As long as you're able to produce a valid equation for the pattern of the sequence, there's nothing anyone can say to reject your result.

That is true - but often, examination questions in particular, ask you to sometimes give your answer in a certain form - which can at time deviate from the simple sequence rule.
Title: Re: Homework Section
Post by: Kitsune on October 06, 2010, 09:00:10 am
If such a restriction applied, it'd have to be explicitly stated somewhere.
Title: Re: Homework Section
Post by: ~Legend~ on October 07, 2010, 12:54:29 am
If such a restriction applied, it'd have to be explicitly stated somewhere.

Yep, ideally. Unless the topic you are working on is generally followed through one form. ;)
Title: Re: Homework Section
Post by: Daco on April 08, 2011, 09:20:14 pm
I need some math challenges. :cool:
Title: Re: Homework Section
Post by: Caltson on April 08, 2011, 09:41:22 pm
I need some math challenges. :cool:

Easter Holiday starts tomorrow, The only math challenge you can get is counting the amount of eggs the easter bunny brought to you  :lol:
Title: Re: Homework Section
Post by: Que on April 08, 2011, 10:10:57 pm
Wow, I look at these math solutions and I get all confused from the very beginning.  :lol:
Title: Re: Homework Section
Post by: Jubin on April 08, 2011, 10:24:39 pm
I need some math challenges. :cool:
Three men, Adam, Bertie and Charlie, agree to take part in a lethal three-way duel. They each have a pistol and several rounds of ammo, and they draw lots to see who will shoot first and who second. Then they stand an equal distance apart, and they take turns to fire. When it is a player's turn, he can take one shot at any target of his choice, then the turn passes to the next player. The duel continues until only one player is left alive.

For simplicity, we can ignore the possibility of a player becoming injured and unable to shoot: a player is either alive or dead. We also assume that each player chooses to play in such a way as to give himself the best chance of winning.

Now Adam will always kill the person he shoots,Bertie hits 80% of the times and  Charlie is only a moderate shot and will only hit 50% of the times. All three men know this.

Of the three men, who has the best chance of winning the duel? Which are the surviving chances for the others. With the calculations please : )
Title: Re: Homework Section
Post by: JDC on April 08, 2011, 10:27:47 pm
You're not alone. :lol:
 
I saw this topic, and now I love this community even more.
 
Now, a simple trick question for all the smart minds here. Let's see if you can get it on the first try reading.
 
A bald lady lives in a yellow house. She wears yellow clothes, has yellow furniture, everything in the house is yellow. Later in the day, she rode a yellow taxi with a driver wearing yellow to the nearby mall, paying 3 kroner in fees. The mall is also colored yellow on the walls, the floor, the ceiling, and so is all their merchandise, and the lady shops for a day before riding home in another yellow cab. At this point, her eyes are already strained from yellow fatigue after using a yellow computer. When she looked at herself in the mirror after a tiring day, she was holding a green comb but she did not use it.
 
Why didn't she use it?
Title: Re: Homework Section
Post by: happyday on April 08, 2011, 10:34:35 pm
she is bald yo, unless she did use it -- but on her pubic hair?
Title: Re: Homework Section
Post by: JDC on April 08, 2011, 10:42:09 pm
It's always more confusing when told in person. Heh. Anyways, another one.
 
Imagine Gandalf is on vacation in Libya when the war erupts. When he went there, he wanted to build a sauna.
 
In a night of war, dozens of armies unleash legions of bombs upon the country, changing the night sky from black to yellow. The effect of the mass napalm shower makes itself felt in Libya, the light from the fires in the sky is bright enough to read a newspaper inside a forest at midnight. After this night, Gandalf does not need to build a sauna anymore.
 
Why does Gandalf no longer need to build a sauna?
Title: Re: Homework Section
Post by: Daco on April 08, 2011, 11:09:08 pm
Three men, Adam, Bertie and Charlie, agree to take part in a lethal three-way duel. They each have a pistol and several rounds of ammo, and they draw lots to see who will shoot first and who second. Then they stand an equal distance apart, and they take turns to fire. When it is a player's turn, he can take one shot at any target of his choice, then the turn passes to the next player. The duel continues until only one player is left alive.

For simplicity, we can ignore the possibility of a player becoming injured and unable to shoot: a player is either alive or dead. We also assume that each player chooses to play in such a way as to give himself the best chance of winning.

Now Adam will always kill the person he shoots,Bertie hits 80% of the times and  Charlie is only a moderate shot and will only hit 50% of the times. All three men know this.

Of the three men, who has the best chance of winning the duel? Which are the surviving chances for the others. With the calculations please : )

Already started doing it but it's late... *sleepy* I'll finish it tomorrow. :D
Title: Re: Homework Section
Post by: MrFrancis on April 09, 2011, 05:07:13 am
It's always more confusing when told in person. Heh. Anyways, another one.
 
Imagine Gandalf is on vacation in Libya when the war erupts. When he went there, he wanted to build a sauna.
 
In a night of war, dozens of armies unleash legions of bombs upon the country, changing the night sky from black to yellow. The effect of the mass napalm shower makes itself felt in Libya, the light from the fires in the sky is bright enough to read a newspaper inside a forest at midnight. After this night, Gandalf does not need to build a sauna anymore.
 
Why does Gandalf no longer need to build a sauna?

Coz it has an 'atmospheric' sauna already in Libya
Title: Re: Homework Section
Post by: Call_me_Dad on April 09, 2011, 12:56:36 pm
Three men, Adam, Bertie and Charlie, agree to take part in a lethal three-way duel. They each have a pistol and several rounds of ammo, and they draw lots to see who will shoot first and who second. Then they stand an equal distance apart, and they take turns to fire. When it is a player's turn, he can take one shot at any target of his choice, then the turn passes to the next player. The duel continues until only one player is left alive.

For simplicity, we can ignore the possibility of a player becoming injured and unable to shoot: a player is either alive or dead. We also assume that each player chooses to play in such a way as to give himself the best chance of winning.

Now Adam will always kill the person he shoots,Bertie hits 80% of the times and  Charlie is only a moderate shot and will only hit 50% of the times. All three men know this.

Of the three men, who has the best chance of winning the duel? Which are the surviving chances for the others. With the calculations please : )

I tried this:

There are 6 permutations for the draws: (representing the order of who shoots after who):
1 ABC
2 ACB
3 BAC
4 BCA
5 CAB
6 CBA

Each draw has a probability of 1/6=0.16

Lets calculate the probability of A winning the battle=
Sum of probabilities of A winning the battle in all six cases=
Case 1: ABC
P(event) denotes the probability of occurrence of 'event'

Case1 && A shoots B && C misses A = P(Case1) x P(A shoots B) x P(C misses A)
=0.16 x 1 x 0.5
=0.08

Case 2: ACB
Case2 && A shoots B && C misses A = P(Case1) x P(A shoots B) x P(C misses A)
=0.08

Case 3: BAC
Case3 && B misses A && A shoots B && C misses A = P(Case3) x P(B misses A) x P(C misses A)
=0.16 x 0.2 x 0.5
=0.016

Case 4: BCA
Case4 && B misses A && C misses A && C misses A again = P(Case4) x P(B misses A) x P(C misses A) x P(C misses A)
=0.16 x 0.2 x 0.5 x 0.5
=0.008

Case 5: CAB
Case5 && C misses A && C misses A again = P(case5) x P(C misses A) x P(C misses A)
=0.16 x 0.5 x 0.5
=0.04

Case 6: CBA
P(Case6) x P(C misses A) x (B misses A) x P(C misses A)
=0.16 x 0.5 x 0.2 x 0.5
=0.008

So probability of A winning the threesome=0.08 + 0.08 + 0.016 + 0.008 + 0.04 + 0.008= 0.232

Some1 else calculate plssss....ima sleep now
Title: Re: Homework Section
Post by: Jubin on April 09, 2011, 01:04:30 pm
I have to say  that Call_Me_Dad already has mistakes in his train of thoughts.
Title: Re: Homework Section
Post by: Ayden on April 09, 2011, 01:34:22 pm
From the way I see it, Charlie has the best chance at winning if he has knowledge to win even if he is the worst shooter. He will just shoot and aim at pure air in order to prevent the two others to shoot at him. So Charlie has a 2/3 chance to win, while the two others have just 1/3 chance to win as they will shoot at each other if they get drawn.
I figured this out since you said yourself that they all knew who were shooting the best and who weren't :)
Not sure on the calculation part though.
Correct me if my theory is wrong ;)
Title: Re: Homework Section
Post by: Altair_Carter on April 09, 2011, 01:39:10 pm
A trick question:

What colour would chameleon be if you put him in a mirror room?
Title: Re: Homework Section
Post by: JDC on April 09, 2011, 01:48:08 pm
Can it become transparent? :lol:
Title: Re: Homework Section
Post by: Daco on April 09, 2011, 01:59:56 pm
I will refer to Adam: A, Bertie: B and Charles: C.
A does 100% damage and the target dies.
B does 80% damage.
C does 50% damage.

Now, who will begin shooting first, then who will begin shooting second, so each player's turn will be clear? Since they'll play lottery to determine it, this is where probabilities come in.
I will take each case alone: If A starts shooting, or B starts shooting, or C starts shooting.

Since it has been 3 years since I studied probabilities in school, I'll use l'arbre de choix or what we call selection tree in English, or close to it.

1st scenario: If A starts shooting:

(http://img641.imageshack.us/img641/5813/72447306.png)

The lines linking a letter to another is the trajectory of the bullet from the left to the right. Equal signs move on to the next action in the same scenario.

2nd scenario: If B starts shooting:

(http://img217.imageshack.us/img217/9929/28013774.png)

3rd scenario: If C starts shooting:

(http://img816.imageshack.us/img816/8836/87023889.png)

Now we count the chances.

It's obvious that A has the most winning chances, now let's count B's chance and C.

B's chances are 7 wins out of total 24 wins. So his chance his 7/24 of winning, which is approximately 29 %.

Same goes for B.

Cheers :girl:
Title: Re: Homework Section
Post by: Drastic on April 09, 2011, 02:04:20 pm
fucking amazed
Title: Re: Homework Section
Post by: Daco on April 09, 2011, 02:07:29 pm
f**king amazed

 :girl:



also guys, maths or gtfo
Title: Re: Homework Section
Post by: Jubin on April 09, 2011, 02:35:13 pm
Daco - For simplicity, we can ignore the possibility of a player becoming injured and unable to shoot: a player is either alive or dead.
So no 50% alive option.

I am not amazed at all.

From the way I see it, Charlie has the best chance at winning if he has knowledge to win even if he is the worst shooter. He will just shoot and aim at pure air in order to prevent the two others to shoot at him. So Charlie has a 2/3 chance to win, while the two others have just 1/3 chance to win as they will shoot at each other if they get drawn.
I figured this out since you said yourself that they all knew who were shooting the best and who weren't :)
Not sure on the calculation part though.
Correct me if my theory is wrong ;)
Ayden you do realize, that shooting into the air does not prevent others from shooting him. Because once A or B is dead. they will shoot C.
Title: Re: Homework Section
Post by: Daco on April 09, 2011, 02:50:13 pm
Daco - For simplicity, we can ignore the possibility of a player becoming injured and unable to shoot: a player is either alive or dead.
So no 50% alive option.

I am not amazed at all.
Ayden you do realize, that shooting into the air does not prevent others from shooting him. Because once A or B is dead. they will shoot C.

That's what I did... the "drops" or "loses"  signs are just to clarify how the person dies..

Is the calculus correct?
Title: Re: Homework Section
Post by: Jubin on April 09, 2011, 03:11:14 pm
Nope Daco it's not. Let's for example take both of your 1st scenario ones. A) They would be that, A has 50% chance of surviving and C has 50% of surviving.
B) A has 20% chance of surviving and B has 80% chance of surviving.
Survivng chance does not mean that A does have another chance of shooting.

You can check Call_Me_Dad's calculations and his logic how the system works.
Title: Re: Homework Section
Post by: Daco on April 09, 2011, 06:58:30 pm
Since the three men's shooting strategies will depend on the higher their chances will be, I will try to do this with logic..

If Adam is the one that shoots first, he will be shooting Bertie to eliminate his chance so that only Charlie remains (the guy with the lowest aim accuracy). Now it's Charlie's turn to shoot, Adam gets owned with 50% chance of killing him.

Charlie now has 50% chance of winning, and Adam 50%.

If Bertie shoots first, He shoots at Adam first to prevent himself from a possible kill.

In summary, if Bertie shoots, Charlie will have 50% chance, Bertie 32,5% and Adam 17,5%.

If Charlie chooses to shoot, he obviously will not shoot because he will f**k it up, so he misses so the other two will mess it up and he gets a free pass. In this case, we'll return to one of the previous scenarios.

Overall, Charlie has the highest chance of winning (50%), Adam 33,75% and Bertie 16,25%.

FUUUUUUUUUUUUUUUUUUUUUUUUCK my head hurts like f**k.

Although I'm sure my calculus is wrong, but at least I made a progress. :D

Post Merge: April 09, 2011, 07:00:02 pm
Pardon, Jubin. My logic at the start was very wrong and I didn't clearly read your riddle very well, I hope this one isn't as much screwed... :razz:
Title: Re: Homework Section
Post by: Jubin on April 09, 2011, 07:17:04 pm
Yes Daco, you have made progress and this one isn't so screwed, but you still have a long way to go.

Title: Re: Homework Section
Post by: Daco on April 09, 2011, 07:43:28 pm
So we agree that Charlie is the guy with the most winning chances, correct?

What else now?
Title: Re: Homework Section
Post by: Call_me_Dad on April 11, 2011, 11:55:20 am
Im not sure where did i go wrong :(

Maybe this problem will involve Baye's Theorem.
Title: Re: Homework Section
Post by: Jubin on April 11, 2011, 10:45:03 pm
Call_Me_Dad, you didn't give much of a thought that maybe at some cases it is good when Charlie misses on purpose.
Title: Re: Homework Section
Post by: Daco on April 03, 2012, 11:23:05 am
Bump.

Post Merge: April 03, 2012, 11:31:15 am
Are you sitting alone at home, and stuck with your homewoks?
You will be helped as much as possible by replieing here.
Try us out with any subjects, math, biology, geography, physics/chemistry, anything :)
Who knows? Maybe you'll get surprised, and get the excact help your looking for, perhaps even in foreign languages too:)
But for your own sake, do not ask for help if you haven't tried to do the job by yourself ;)
Try by yourself before you ask :)
Everyone is always welcome to ask for the help they need :)
I think that this topic will be a very helpfull topic for many people :)
Thanks.

Best Regards
Custom
Title: Re: Homework Section
Post by: duffman on April 03, 2012, 11:47:47 am
(http://24.media.tumblr.com/tumblr_m0c5wrOx9C1r9w47to1_400.gif)
Title: Re: Homework Section
Post by: Matt Murdock on April 03, 2012, 01:29:17 pm
(http://24.media.tumblr.com/tumblr_m0c5wrOx9C1r9w47to1_400.gif)
Ok any Geography geeks here?
Title: Re: Homework Section
Post by: Daco on April 03, 2012, 06:26:09 pm
Ok any Geography geeks here?

Sorry I do either math or physics

well you use google for that

right?
Title: Re: Homework Section
Post by: ElMartu on April 03, 2012, 10:23:38 pm
i can into geography

everyone can, you just google it
Title: Re: Homework Section
Post by: Daco on April 06, 2012, 09:56:26 am
Bump.
Title: Re: Homework Section
Post by: Jimmylicious on April 08, 2012, 09:39:26 pm
cant understand maths. If anyone willing to help, give me Q.
Title: Re: Homework Section
Post by: Jubin on April 09, 2012, 06:46:47 am
cant understand maths. If anyone willing to help, give me Q.
"Math is the lesbian sister of biology." - Peter Griffin

Also Daco is willing to help you.
Title: Re: Homework Section
Post by: Daco on April 09, 2012, 09:18:51 am
cant understand maths. If anyone willing to help, give me Q.
(http://i39.tinypic.com/3spwj.png)
Title: Re: Homework Section
Post by: Jimmylicious on April 09, 2012, 04:46:04 pm
Pyramid base border length is 1dm (1dm-10cm) and the corner between side edge and the base  (<ADS) =60 degrees (i dont know, google translator told me so lol)
1) count the piramids base longest diagonal lenght (AD=BE=FC)
(http://desmond.imageshack.us/Himg38/scaled.php?server=38&filename=p3220027.jpg&res=landing)

Post Merge: April 09, 2012, 05:16:04 pm
dont even know where to start and with what.
Title: Re: Homework Section
Post by: Freedom on April 09, 2012, 07:43:34 pm
Pyramid base border length is 1dm (1dm-10cm) and the corner between side edge and the base  (<ADS) =60 degrees (i dont know, google translator told me so lol)
1) count the piramids base longest diagonal lenght (AD=BE=FC)
(http://desmond.imageshack.us/Himg38/scaled.php?server=38&filename=p3220027.jpg&res=landing)

Post Merge: April 09, 2012, 05:16:04 pm
dont even know where to start and with what.


in a 6 corner pyramid R = a (radius of the outer circle)
therefore  2R = 2a = 20
Title: Re: Homework Section
Post by: Patton on April 09, 2012, 08:09:31 pm
Pyramid with a six-sided base is consisted out of six equilateral triangles (the ones with all three sides equal). Since you're given the total length of the outer border, the length of one side of one triangle is one sixth of the total length: 10/6 or 5/3 for short. Obviously, the lengths of the other two sides of one triangle will be the same. The longest diagonal will be between two points on the base which are opposite from each other (in this case AD or BE or CF). Then the length is just double the size of the length of the side of one of the triangles in the base, so (5 * 2) / 3 or 10/3.
Title: Re: Homework Section
Post by: Mario_Rinna on April 09, 2012, 08:13:02 pm
Pyramid with a six-sided base is consisted out of six equilateral triangles (the ones with all three sides equal). Since you're given the total length of the outer border, the length of one side of one triangle is one sixth of the total length: 10/6 or 5/3 for short. Obviously, the lengths of the other two sides of one triangle will be the same. The longest diagonal will be between two points on the base which are opposite from each other (in this case AD or BE or CF). Then the length is just double the size of the length of the side of one of the triangles in the base, so (5 * 2) / 3 or 10/3.
(http://dl.dropbox.com/u/48339001/463244809.jpg)
Title: Re: Homework Section
Post by: Daco on April 09, 2012, 09:28:22 pm

in a 6 corner pyramid R = a (radius of the outer circle)
therefore  2R = 2a = 20

a = 10/6

I think he meant by 'border length' the perimeter of the base.
Title: Re: Homework Section
Post by: JayL on April 10, 2012, 04:12:03 am
Ok any Geography geeks here?

What do you need? Physical geography, cartography, geopolitics, ...?
Title: Re: Homework Section
Post by: ElMartu on April 10, 2012, 04:19:53 am
Pyramid with a six-sided base is consisted out of six equilateral triangles (the ones with all three sides equal). Since you're given the total length of the outer border, the length of one side of one triangle is one sixth of the total length: 10/6 or 5/3 for short. Obviously, the lengths of the other two sides of one triangle will be the same. The longest diagonal will be between two points on the base which are opposite from each other (in this case AD or BE or CF). Then the length is just double the size of the length of the side of one of the triangles in the base, so (5 * 2) / 3 or 10/3.

I couldn't have done it myself but after reading your explanation man it's easy as fuck
Title: Re: Homework Section
Post by: JDC on April 11, 2012, 02:57:33 pm
I couldn't have done it myself but after reading your explanation man it's easy as f**k

A problem is that the system overall trains people these days to stick exclusively to scientific methods instead of using common sense every now and then.

An example was the last remedial math test (basic math, as we call it) we had last academic year (we have two math subjects; regular math with advanced algebra, trigonometry, and statistics, and basic math since my school's population were getting more dull in math)... the majority of my classmates failed to answer the following problem.

"Here is a number line from 0 to 1. First, plot 1/2 on the number line. Next, choose a fraction smaller than 1/2 and plot that on the number line as well. Afterwards, explain why you placed the two fractions in their respective locations."
Title: Re: Homework Section
Post by: Daco on April 11, 2012, 10:18:03 pm
A problem is that the system overall trains people these days to stick exclusively to scientific methods instead of using common sense every now and then.

An example was the last remedial math test (basic math, as we call it) we had last academic year (we have two math subjects; regular math with advanced algebra, trigonometry, and statistics, and basic math since my school's population were getting more dull in math)... the majority of my classmates failed to answer the following problem.

"Here is a number line from 0 to 1. First, plot 1/2 on the number line. Next, choose a fraction smaller than 1/2 and plot that on the number line as well. Afterwards, explain why you placed the two fractions in their respective locations."

??????

1/2 cuts the segment in two and 1/4 cuts the first half in two

did i win???
Title: Re: Homework Section
Post by: ElMartu on April 11, 2012, 10:25:22 pm
I'd place the fractions where I placed them because that's where they actually go: 1/2 goes in the exact middle of the line and and the other fraction can go whenever I want as long as it's smaller than 1/2
Title: Re: Homework Section
Post by: JDC on April 12, 2012, 05:51:25 am
??????

1/2 cuts the segment in two and 1/4 cuts the first half in two

did i win???

Correct. This was my answer as well. My classmates failed because they were too busy ignoring common sense.



I'd place the fractions where I placed them because that's where they actually go: 1/2 goes in the exact middle of the line and and the other fraction can go whenever I want as long as it's smaller than 1/2

The problem would be explaining why the fraction of the said value goes into the appropriate place in the number line. An example would be a classmate of mine who chose 1/6 after plotting 1/2, only he did not know how to explain it. :D
Title: Re: Homework Section
Post by: Daco on April 12, 2012, 07:59:58 pm
Correct. This was my answer as well. My classmates failed because they were too busy ignoring common sense.



The problem would be explaining why the fraction of the said value goes into the appropriate place in the number line. An example would be a classmate of mine who chose 1/6 after plotting 1/2, only he did not know how to explain it. :D

Ok this is something I have learnt from college.

We have a segment AB and we want to cut it in 3 equal pieces. We draw for example any line starting from A other than the perpendicular to (AB) then we take the compass (or ruler) and start making even pieces as shown:

(http://www.irem.univ-montp2.fr/archi/mathimg/base/div31.gif)

Then we link the end of our created equal parts to the end B of our segment and we draw parallel lines to that line in each end. Well maybe my explanation sucks but you get the point when you see this:

(http://www.irem.univ-montp2.fr/archi/mathimg/base/div32.gif)
Title: Re: Homework Section
Post by: Matt Murdock on April 14, 2012, 03:01:24 am
Hi Good Men, Need to write an application for college admission, help me please? If you want I can reward you with In Game money for it.  :devroll:

Here's the quote from the site :
''Please Provide A Personal Statement regarding how your academic achievements, personal interests, and life experiences have helped prepare you to succeed academically and to be an active member of the college community. Be sure your response addresses each of the three components. (Please limit your response to approximately 250 words).''
Title: Re: Homework Section
Post by: ElMartu on April 14, 2012, 05:45:42 am
Well the fact you're asking an online gaming forum to write it for you doesn't say good things about your academic achievements.
Title: Re: Homework Section
Post by: JDC on April 14, 2012, 08:10:47 am
Hi Good Men, Need to write an application for college admission, help me please? If you want I can reward you with In Game money for it.  :devroll:

Here's the quote from the site :
''Please Provide A Personal Statement regarding how your academic achievements, personal interests, and life experiences have helped prepare you to succeed academically and to be an active member of the college community. Be sure your response addresses each of the three components. (Please limit your response to approximately 250 words).''

You do realize you are the only one in a position that would grant you sufficient knowledge to answer that question...
Title: Re: Homework Section
Post by: Daco on April 14, 2012, 11:33:27 am
You do realize you are the only one in a position that would grant you sufficient knowledge to answer that question...
I think he's trolling. Well, if not, then I've got some bad news for you son...
Title: Re: Homework Section
Post by: Matt Murdock on April 14, 2012, 03:24:39 pm
I think he's trolling. Well, if not, then I've got some bad news for you son...
Not trolling, Guess I'm screwed then. I got nothing to say, I'm blank on the matter on what to write there. Any ideas at least like what I fill there? I love nature, tress or my past achievements or what? Or Do I put how badly I want to be a member of the college? Its my first time applying for a university.  :(

I know I might be the only one who has sufficient knowledge to answer that but I'm completely blank with no ideas, Even an example would help. Tomorrow is the last day btw. I'm a fast thinker and I can do it, I just don't have an idea on what to write there.

Well the fact you're asking an online gaming forum to write it for you doesn't say good things about your academic achievements.
I realized that, but anything regarding this, like a past college application, any example paragraph anything. Would help alot!
Title: Re: Homework Section
Post by: JDC on April 14, 2012, 04:56:15 pm
Some guide questions...

- Why are you applying for this university?
- What have you accomplished in your education so far?
- What events have helped you succeed in your life so far?
- How are you prepared to be an active member of the college community?

Something around those lines, so you can answer the three main components they asked of you...
Title: Re: Homework Section
Post by: Matt Murdock on April 14, 2012, 08:29:19 pm
Some guide questions...

- Why are you applying for this university?
- What have you accomplished in your education so far?
- What events have helped you succeed in your life so far?
- How are you prepared to be an active member of the college community?

Something around those lines, so you can answer the three main components they asked of you...
Thank You!  :hurray: :banana: :bow:

Post Merge: April 15, 2012, 04:05:27 pm
So Coming to it, I wrote this, I'm not sure why I am posting it here, maybe for an opinion on how I did from not having any ideas an hour ago to what I wrote now.

Quote
So, This is the point in my life when I truly realize who I want to become and what I have to do to achieve it. Becoming a student of the University of _______ is a priority to me, being it based in such a wonderful city of _________ and having an exceptional alumni, I'm not sure why but I personally feel connected to the city of ______, like I have always belonged to the place, thus playing a major role in my choice to further my studies after high school.

Throughout my life, I've had different types of achievements during school and outside, Like everyone I have had my ups and downs, from being a topper always in class to getting unbelievably low grades. But I never gave up and always fought back , to the date, which I consider my main power , Sometimes In life some incidents take place which may break you far more than you can imagine, but you should learn and come back even more powerful each time. And yet I continue on it and wish to take it further to where I once used to be or even ahead of that. I may not be perfect but I tend to work on becoming one.

Since day one, learning foreign languages and foreign culture has been a hobby to me, Like an addiction, More than any other subject those which of literature , languages etc. have always pulled me towards them, May I be weak in mathematics, but I make that up in the subjects where I study the theory and literature.  Reading of different places and learning about them, different people , different stories have always attracted me towards them, When it comes to studying I'm more of a explorer or adventurer , I like to study in a fun way and I like to help others understand it as well.

As already stated becoming a member of the UC community is very essential for me and I would consider myself very lucky if chosen. Being from the different culture I am, I'm sure I can not only learn but set an example for others as well of what UC represents , unity and variations in cultures with people coming from different backgrounds to share theirs and gain more knowledge.
Title: Re: Homework Section
Post by: Daco on April 19, 2012, 06:30:30 pm
So you all solved all your homework and done everything correctly and don't need any help or assistance and all that shit?

(http://myfacewhen.com/i/476.jpg)

OK.
Title: Re: Homework Section
Post by: Julio. on April 19, 2012, 09:32:02 pm
Thank You!  :hurray: :banana: :bow:

Post Merge: April 15, 2012, 04:05:27 pm
So Coming to it, I wrote this, I'm not sure why I am posting it here, maybe for an opinion on how I did from not having any ideas an hour ago to what I wrote now.

How can you benefit this college as a community?

Are you a thinker, comedian, outgoing?

Why should they pick you over a student with better grades, think, what have you got they haven't?
Title: Re: Homework Section
Post by: Karmps. on April 19, 2012, 09:36:45 pm
I need some help with mine too, if I cant understand it I will definately post it here  :lol:
Title: Re: Homework Section
Post by: Gimli on April 19, 2012, 10:36:17 pm
There are tons of UCAS Personal Statement examples on the Internet, entire websites dedicated to them actually.. Just make sure you don't copy anything as they have auto-plagiarism systems.

Try to prove that you actually care about the subject rather than people who just apply thinking "degree=good job=money=kthx want to be stuck with a job I won't like for the rest of my life" and drop out in the first year, especially if you are applying for a business degree :D
Title: Re: Homework Section
Post by: ElMartu on April 19, 2012, 11:10:40 pm
SOMEBODY POST MATHS
Title: Re: Homework Section
Post by: Jubin on April 20, 2012, 09:19:28 pm
SOMEBODY POST MATHS
There's really no point as most of math solutions are available on the net. But sure if you want some for your own pleasure I can give you some integration exercises. ∫(2dx)/[x(x2+2x+2)] ∫dx/(x2+4x+8). There you go, have fun.
Title: Re: Homework Section
Post by: ElMartu on April 20, 2012, 09:25:36 pm
i cannot into integrals

sry

try something a 12 year old can do
Title: Re: Homework Section
Post by: Jubin on April 20, 2012, 09:31:54 pm
i cannot into integrals

sry

try something a 12 year old can do
Don't worry Daco will get those. Also math that 12 year olds can do differ quite a lot from country to country.
Title: Re: Homework Section
Post by: duffman on April 20, 2012, 09:43:57 pm
Drop a soluble product on a glass of water. In instants in (t), in minutes, the amount of the product not dissolved its, in grams, given by the function:

(http://img694.imageshack.us/img694/977/semttuloev.png)

Question - How much is the amount of the product droped initially on the water?
Title: Re: Homework Section
Post by: Matt Murdock on April 21, 2012, 06:52:05 am
How can you benefit this college as a community?

Are you a thinker, comedian, outgoing?

Why should they pick you over a student with better grades, think, what have you got they haven't?
Thinker, Comedian and outgoing part is good as well as the last one. Since I do not get the best of grades due to my mutiny against my teachers. :redface: But I already submitted the app since 16 April was the last day. :P

There are tons of UCAS Personal Statement examples on the Internet, entire websites dedicated to them actually.. Just make sure you don't copy anything as they have auto-plagiarism systems.

Try to prove that you actually care about the subject rather than people who just apply thinking "degree=good job=money=kthx want to be stuck with a job I won't like for the rest of my life" and drop out in the first year, especially if you are applying for a business degree :D
Haha "degree=good job=money=kthx'' is the real shit! :D However I'm applied for a degree in Journalism or Arts (includes animation and photography) and Architecture , They gave me 3 choices. I wanted to pick Drama but that's a different branch and apps will open in the end of the year. I might apply for that if I don't get into Journalism which I think I can achieve easily due to the inherit trait in me from my dad.
Title: Re: Homework Section
Post by: Patton on April 21, 2012, 06:55:06 am
Drop a soluble product on a glass of water. In instants in (t), in minutes, the amount of the product not dissolved its, in grams, given by the function:

(http://img694.imageshack.us/img694/977/semttuloev.png)

Question - How much is the amount of the product droped initially on the water?
Since your function is time dependent you need to determine which amount to solve it for. If you take that the moment when you drop the solute in the water as t = 0min, that is the time that you can use since the reaction most likely won't start immediately, and the amount of the solute in water will still be at its maximum. Therefore if you replace the time variable you will get something like this:

(http://dl.dropbox.com/u/3131567/duffman.png)

Also, for larger amounts of time you will get remaining amount of solute. After 30 minutes, you'll have 5,05g left and after 60 minutes there will be 0,27g of the solute left.

Protip: if you want to have your solute dissolved in the solvent faster add heat or put your glass into the ultrasound cleaner while stirring.
Title: Re: Homework Section
Post by: Daco on April 21, 2012, 11:14:28 pm
There's really no point as most of math solutions are available on the net. But sure if you want some for your own pleasure I can give you some integration exercises. ∫(2dx)/[x(x2+2x+2)] ∫dx/(x2+4x+8). There you go, have fun.

too easy bro

(http://img338.imageshack.us/img338/742/img0034avt.jpg)(http://img214.imageshack.us/img214/9365/img0033xg.jpg)
Title: Re: Homework Section
Post by: Jubin on April 22, 2012, 12:32:02 am
Interesting way of finding the constant a there. Also how hard of a integrals you want?
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 08:44:17 am
Interesting way of finding the constant a there.

There's nothing into it. Find a quotient where the denominator can be factorised such as this function:
(http://i44.tinypic.com/huefj4.jpg)

Easy to notice that it can be factorized:
(http://i44.tinypic.com/bijswk.jpg)

Do this then:
(http://i42.tinypic.com/2vds02r.png)

If you want A you multiply by its respective denominator and replace the x by the value that makes that denominator 0 (for A it's -3, for B it's 1)

Easy to find that A= -1/4 and B= 1/4

So:
(http://i43.tinypic.com/2da0duw.png)

It's called partial fraction decomposition (http://en.wikipedia.org/wiki/Partial_fraction) in Algebra, but I guess you already know that... :cop:

Also how hard of a integrals you want?

Impossible tier... :cool:

Post Merge: April 22, 2012, 09:33:40 am
Drop a soluble product on a glass of water. In instants in (t), in minutes, the amount of the product not dissolved its, in grams, given by the function:

(http://img694.imageshack.us/img694/977/semttuloev.png)

Question - How much is the amount of the product droped initially on the water?

INB4 THAT'S 3t
Title: Re: Homework Section
Post by: JDC on April 22, 2012, 11:09:11 am
Daco = :cool:

In our country, math for 12 year olds is still where you are introduced to Algebra. Our entire education system is basically shit (which is why I preferred immersing in books for hours compared to the classroom lessons, I'd learn even more) even if they are adding two years.
Title: Re: Homework Section
Post by: Jubin on April 22, 2012, 01:18:37 pm
Daco yeah, I know how to do it but you for some reason wrote there a= lim(x->0) 2/(x^2+2x+2)
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 01:20:06 pm

Post Merge: April 22, 2012, 09:33:40 am
INB4 THAT'S 3t
No, its something called Deriv or smth.
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 03:45:49 pm
Daco yeah, I know how to do it but you for some reason wrote there a= lim(x->0) 2/(x^2+2x+2)

too obvious since 2/(x^2+2x+2) is continuous at 0 so f(0) = lim x->0 f(x)

No, its something called Deriv or smth.

derivate 3??? lol
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 04:15:08 pm
derivate 3??? lol
ye
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 05:19:52 pm
ye

3' = 0

.....................
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 05:37:51 pm
3' = 0

.....................
OBVIOUSLY, SO PATTON IS WRONG?
Title: Re: Homework Section
Post by: Patton on April 22, 2012, 05:49:45 pm
ye
Then it's even easier. Use the same value for time (t = 0min); you'll get something like this as the amount of solute at the beginning:

(http://dl.dropbox.com/u/3131567/duffman2.png)
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 05:52:00 pm
Then it's even easier. Use the same value for time (t = 0min); you'll get something like this as the amount of solute at the beginning:

(http://dl.dropbox.com/u/3131567/duffman2.png)
What you did to the 0.09t ?
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 05:52:57 pm
OBVIOUSLY, SO PATTON IS WRONG?

then it's 60/5= 12g
Title: Re: Homework Section
Post by: Patton on April 22, 2012, 05:54:42 pm
What you did to the 0.09t ?

I took the time as 0 since we can assume that at the very beginning of the reaction (time when the solute was added to the water) there is still the maximum (i.e. all) of the solute present in the non-dissolved state. So, 0,09 * 0 is obviously 0 and e0 is 1.
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 06:01:53 pm
I took the time as 0 since we can assume that at the very beginning of the reaction (time when the solute was added to the water) there is still the maximum (i.e. all) of the solute present in the non-dissolved state. So, 0,09 * 0 is obviously 0 and e0 is 1.

(http://myfacewhen.com/images/361.jpg)

BUT BRO YOU DIDINT NOTICE 3' SO THE EQUATION IS BASICALLY 60/5e^0.006t
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 06:06:02 pm
Drop a soluble product on a glass of water. In instants in (t), in minutes, the amount of the product not dissolved its, in grams, given by the function:

(http://img694.imageshack.us/img694/977/semttuloev.png)

Question n2 - How many time it takes to dissolve 20 grams of the product?
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 06:07:54 pm
Drop a soluble product on a glass of water. In instants in (t), in minutes, the amount of the product not dissolved its, in grams, given by the function:

(http://img694.imageshack.us/img694/977/semttuloev.png)

Question n2 - How many time it takes to dissolve 20 grams of the product?

i don't understand the derivative of 3 is 0 why bother putting it again?????
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 06:10:37 pm
i don't understand the derivative of 3 is 0 why bother putting it again?????
fuck my teacher man, dam hoe
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 06:17:30 pm
wait if 3 doesn't exist then the second question is wrong
Title: Re: Homework Section
Post by: Patton on April 22, 2012, 06:19:39 pm
BUT BRO YOU DIDINT NOTICE 3' SO THE EQUATION IS BASICALLY 60/5e^0.006t
(http://dl.dropbox.com/u/3131567/boris/wellfk.jpeg)
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 06:21:10 pm
(http://dl.dropbox.com/u/3131567/boris/wellfk.jpeg)

shit the whole thing is wrong

(http://myfacewhen.com/images/37.jpg)
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 06:23:05 pm
wait if 3 doesn't exist then the second question is wrong
Probably you should use a graphic calculator, its something about with LOG() / Y= / TABLE... But I don't remember now..

shit the whole thing is wrong
[/quote]
YOU GUYS SUCK MAN
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 06:24:28 pm
Probably you should use a graphic calculator, its something about with LOG() / Y= / TABLE... But I don't remember now..

shit the whole thing is wrong

YOU GUYS SUCK MAN

yes but the question doesn't make sense given that 3' = 0 (supposing there is ' even) the initial product is 12 grams and the question is about dissolving 20grams which isn't logical. at all
before you make any logs or anything
Title: Re: Homework Section
Post by: ElMartu on April 22, 2012, 06:26:05 pm
daco get on msn or something man
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 06:27:50 pm
if there isn't '

initial product is q(0) = 60/(5-3) = 30grams
dissolve 20 grams means q(t)=30-20=60/(5e^0.09t-3) => 5e^0.09t-3=6 => 5e^0.09t = 9 => e^0.09t = 9/5 => 0.09t = ln(9/5) => t=ln(9/5)/0.09 = 6.53096294 minute

FUCK OFF
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 06:33:32 pm
if there isn't '

initial product is q(0) = 60/(5-3) = 30grams
True
Quote
Question n2 - How many time it takes to dissolve 20 grams of the product?
y1=60/5e(0.09t)+3
y2=20

^On the calculator and you will see the graphic and then you will see the intersetion and then the result - 2,202.
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 08:30:57 pm
go suck a duck man, go learn maths

3 has to be there else the whole question wouldn't mean sense. Say we take consideration of the apostrophe on top of the 3. The equation of the remaining product becomes:

q(t)=60/(5e0.09t)

Initial quantity: q(t=0)=60/5=12g

Question 2: How many time it takes to dissolve 20 grams of the product?

When you read the question you see it doesn't mean any sense since the initial quantity is 12g and he's asking for the amount of time to dissolve 20g. If you go ahead and calculate: e0.09t = -60/40 (doesn't mean sense) ; t=ln(-60/40)/0.09 (impossible)
Title: Re: Homework Section
Post by: Patton on April 22, 2012, 08:44:01 pm
Question 2: How many time it takes to dissolve 20 grams of the product?

When you read the question you see it doesn't mean any sense since the initial quantity is 12g and he's asking for the amount of time to dissolve 20g. If you go ahead and calculate: e0.09t = -60/40 (doesn't mean sense) ; t=ln(-60/40)/0.09 (impossible)
It makes sense since the solution can behave according to the function no matter what amount of solute is added into the solvent; it doesn't have to relate to the first question although the result from the first question can come in handy when checking the result you get. The problem is that the function doesn't allow you to determine how much time it takes to dissolve something as it shows the amount of remaining solute. You could try solving with q as 0 since then all solute is dissolved, but then you wouldn't be able to solve the equation. :razz:
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 08:53:26 pm
It makes sense since the solution can behave according to the function no matter what amount of solute is added into the solvent; it doesn't have to relate to the first question although the result from the first question can come in handy when checking the result you get. The problem is that the function doesn't allow you to determine how much time it takes to dissolve something as it shows the amount of remaining solute. You could try solving with q as 0 since then all solute is dissolved, but then you wouldn't be able to solve the equation. :razz:

t = +oo

checkmate
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 11:21:23 pm
t = +oo

checkmate
t = x you don't know, thats what you have to find. Not by those equations, but by the calculator.
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 11:42:56 pm
t = x you don't know, thats what you have to find. Not by those equations, but by the calculator.

ok you're banned from posting










seriously man stop trolling

Post Merge: April 22, 2012, 11:49:12 pm
It makes sense since the solution can behave according to the function no matter what amount of solute is added into the solvent; it doesn't have to relate to the first question although the result from the first question can come in handy when checking the result you get. The problem is that the function doesn't allow you to determine how much time it takes to dissolve something as it shows the amount of remaining solute. You could try solving with q as 0 since then all solute is dissolved, but then you wouldn't be able to solve the equation. :razz:

i don't understand...

how the fuck can you dissolve 20 grams if the maximum solvant you can get from the equation is 12g....????
excluding of course, the time variable t is negative (which is illogical)
Title: Re: Homework Section
Post by: duffman on April 22, 2012, 11:49:39 pm
ok you're banned from posting










seriously man stop trolling
man wtf, I need to get my last 5 points on that shit. I just need that but okay my teacher will do that in the class and I will show to ya'll, holmes
Title: Re: Homework Section
Post by: Daco on April 22, 2012, 11:51:59 pm
ok add [email protected] or [email protected] so i can teach u ok???
ty.
Title: Re: Homework Section
Post by: ElMartu on April 23, 2012, 12:07:58 am
man why you involving me on this

i like, lost myself as soon as you posted the damn equation
Title: Re: Homework Section
Post by: Daco on April 23, 2012, 12:11:19 am
man why you involving me on this

i like, lost myself as soon as you posted the damn equation

add this guy ^ ok?

fast im gonna sleep soon xoxo
Title: Re: Homework Section
Post by: Patton on April 23, 2012, 06:49:22 am
It makes sense mathematically since you get a number in the end, but physically it is nonsense since you can't get negative time. :razz: You can use the results from both questions to conclude and argue that any amount of solute over 12g does not dissolve in the water; instead, it will form a saturated solution with a layer of sediment on the bottom of the glass. So yes, t=∞ would be a very acceptable.
Title: Re: Homework Section
Post by: Jubin on April 23, 2012, 07:11:55 am
Duffman, for the sake of these guys arguing, please check again the initial equation - especially if the denominator is has -3 or -3' or maybe even -3^t.
Title: Re: Homework Section
Post by: duffman on April 24, 2012, 09:12:11 pm
OKAY my teacher made that shit wrong, its only -3 not -3'...


sorry mans :( :( :( :( :( :(
Title: Re: Homework Section
Post by: Daco on May 04, 2012, 06:18:17 pm
Hello.
Title: Re: Homework Section
Post by: Mikal on May 07, 2012, 12:28:57 am
1+1=2
Title: Re: Homework Section
Post by: Daco on May 07, 2012, 08:07:35 pm
1+1=2

1+1 = 1

its 2012 u no  ? ? ? ? ?
Title: Re: Homework Section
Post by: Mopreme on September 26, 2012, 05:34:33 pm
Hi, everyone.
If there is anyone out there who is good at analyzing sentences (finding direct object, indirect object etc. as well as clauses such as post modifying clauses, adverbial clauses etc.) then please PM me. I would really appreciate some help here, and I am willing to pay for it.
Thanks in advance.
 
Title: Re: Homework Section
Post by: Marcel on September 26, 2012, 07:32:31 pm
Didn't even knew this topic existed!

If anyone needs help, just let me know, i can help on the following subjects:

- Aviation (aerodynamics, physics, maths, mechanics, air data systems, cockpit instruments, weather, air law and regulations and more)
- Information Security
- Economics and management
Title: Re: Homework Section
Post by: duffman on September 26, 2012, 07:36:54 pm
History of France anyone???
Title: Re: Homework Section
Post by: Lionel Valdes on September 27, 2012, 03:47:36 pm
Say it has colonised Morocco in the 50's.
Title: Re: Homework Section
Post by: duffman on September 27, 2012, 08:35:43 pm
Say it has colonised Morocco in the 50's.
NO, Luis XIV
Title: Re: Homework Section
Post by: Marcel on September 28, 2012, 05:17:38 pm
XIV was killed using a guillotine when Napoleon took over. Any more questions?
Title: Re: Homework Section
Post by: Lionel Valdes on September 28, 2012, 07:50:42 pm
Ask your parents if they know something, take some sentences from a Wikipedia article..
Title: Re: Homework Section
Post by: ElMartu on September 28, 2012, 08:51:01 pm
they got crushed by germany 2.5 times
Title: Re: Homework Section
Post by: Jubin on September 28, 2012, 11:50:47 pm
XIV was killed using a guillotine when Napoleon took over. Any more questions?
I have one question. What have you been smoking?
Title: Re: Homework Section
Post by: Teddy on September 29, 2012, 12:06:04 am
I have one question. What have you been smoking?

Hes dutch, that question has an obvious answer ;)  :D
Title: Re: Homework Section
Post by: Marcel on September 29, 2012, 02:22:40 am
Hes dutch, that question has an obvious answer ;)  :D

 :weed: :weed: :weed: :weed: :weed: :cool:
Title: Re: Homework Section
Post by: duffman on September 29, 2012, 11:43:45 pm
XIV was killed using a guillotine when Napoleon took over. Any more questions?
Your banned from this topic.
Title: Re: Homework Section
Post by: Marcel on September 30, 2012, 09:30:24 pm
Your banned from this topic.

 :cry:
Title: Re: Homework Section
Post by: Omar Aly on September 30, 2012, 09:45:43 pm
Need help in economics, i have test tomorow....

In Demand Graphic / Chart

What's diffrent between line movment and line shift.. when does each happen, and would be great if you post examples
Title: Re: Homework Section
Post by: Inposible on September 30, 2012, 09:49:26 pm
I suck so bad at maths...
14.13 Are dots X, Y and Z located on the same straight? Explain the answer!

A)XY = a XZ = 3a, YZ=4a
B) XY = a, YZ =2a +1, YZ = 3a     
C)XY = a +2, YZ = 3a +2, YZ = 2a
D)XY = 5, YZ = a +2, YZ =2a +7

Thats my Geometry homework, can anyone explain what is what, i dont understand a thing ^_^
Title: Re: Homework Section
Post by: ElMartu on September 30, 2012, 10:08:41 pm
compound equations
Title: Re: Homework Section
Post by: Omar Aly on September 30, 2012, 10:11:42 pm
First of all if you don't understand this then you'll suffer in geometery :P


simply thoose equations are all compound, meaning they are not congrunt, but some how related to each other..
Title: Re: Homework Section
Post by: Inposible on October 02, 2012, 07:43:39 pm
First of all if you don't understand this then you'll suffer in geometery :P


simply thoose equations are all compound, meaning they are not congrunt, but some how related to each other..

Thanks for response, my teacher explained it to me.
Title: Re: Homework Section
Post by: Jubin on January 26, 2013, 07:36:20 am
A uniform meter ruler AB of weight 0.95N is supported on a knife edge placed at 45 cb from A. The meter ruler balances horizontally when a mass of 48 g is suspended at a distance x from A. Find the value of x.
What you mean by suspended? As in 48g is taken off the ruler? Because that doesn't make sense. Would make a lot more sense if you'd put the 48g mass on the side of the ruler that is 45cm long to balance it out and as far as I calculated that would be on the 20cm mark. Although I might have made some mistakes somewhere.
Title: Re: Homework Section
Post by: Jellyfish on January 26, 2013, 07:58:26 am
A uniform meter ruler AB of weight 0.95N is supported on a knife edge placed at 45 cm from A. The meter ruler balances horizontally when a mass of 48 g is suspended at a distance x from A. Find the value of x.

It would help if you were to provide a rough diagram of the situation. Although it seems pretty simple if you apply the principle of moments. Convert the distance from cm into meters and the weight from grams into newtons and equate.
Title: Re: Homework Section
Post by: chichibung on January 26, 2013, 08:39:12 pm
WTF SOMEBODY HACKED MY ACOUNT, IM ONLY 11 AND I DONT UNDERSTAND WHAT THAT MEANS, WTF WTF WTF WTF WTF WTF, i think i know who it is
Title: Re: Homework Section
Post by: Duel on January 27, 2013, 03:31:02 pm
WTF SOMEBODY HACKED MY ACOUNT, IM ONLY 11 AND I DONT UNDERSTAND WHAT THAT MEANS, WTF WTF WTF WTF WTF WTF, i think i know who it is
:roll:
Title: Re: Homework Section
Post by: Matt Murdock on January 27, 2013, 10:53:48 pm
Ok, I need some help with my photoshop homework, I need to create a magazine cover but I can't find an image, can anyone please help me find an image of a girl/lady/woman standing and posing? Whichever you may feel like, but she must be cute/good looking, preferably blonde and wearing a dress or a gown.

Must be without a watermark on them and in high res.  i.e. time to suggest pictures of your favorite actress/model.  :devroll:

Something like these will do, without water mark tho.

(http://i.istockimg.com/file_thumbview_approve/18352074/2/stock-photo-18352074-cute-teen-posing-in-golden-grasses.jpg)
(http://img541.imageshack.us/img541/5154/79828810151680268179992.jpg)
(http://img7.imageshack.us/img7/2345/6595132portraitofcheerf.jpg)
(http://img255.imageshack.us/img255/9283/emmastonevoguejuly20122.jpg)
Title: Re: Homework Section
Post by: ~Legend~ on January 28, 2013, 07:33:13 pm
WTF SOMEBODY HACKED MY ACOUNT, IM ONLY 11 AND I DONT UNDERSTAND WHAT THAT MEANS, WTF WTF WTF WTF WTF WTF, i think i know who it is

The best place to seek help would be through one of the Argonath Administration areas.

If you like, send me a PM regarding the problem and I can give you a hand.
Title: Re: Homework Section
Post by: Skalleper on January 28, 2013, 07:46:34 pm
So, I got this one for you guys, but be prepared it might be tricky....

1+1?
The answer is, beleve it or not...... 2!!!!!!!!!!!!!!!!!
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